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stiv31 [10]
4 years ago
6

Write 10 to the 7 power in standard form

Mathematics
2 answers:
Makovka662 [10]4 years ago
5 0
Hello!

<span>10000000. An easy way to solve this is to use the 'EE' function on your scientific calculator.</span>
nikklg [1K]4 years ago
3 0

Answer: 10000000

Step-by-step explanation: Let's start with the decimal 1<em>.</em>0. The exponent of 7 tells us to move the decimal point 7 places to the right. Now, we fill in the missing positions with zeroes and we get 10000000.

If you wanted to, you could also multiply 10 seven times and you will get the same exact answer. I would recommend using the first method however of starting with 1.0 and moving the decimal point.

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MA_775_DIABLO [31]

Answer:

  a) maximum; the parabola opens downward

  b) positive; it must lie above the x-axis

  c) x = 1.5

Step-by-step explanation:

The x-intercepts of a function are the points where the graph of the function crosses the x-axis. The y-values there are zero.

The "differences" of a function are related to the average slope between adjacent points. Second differences are related to the rate of change of the slope of the function. When <em>second differences are negative</em>, as here, the slope of the quadratic function is decreasing, becoming more negative. We say the <em>curvature</em> of the function is <em>negatve</em>, and that it <em>opens downward</em>.

__

<h3>a, b.</h3>

If the graph of the parabola opens downward, and it crosses the x-axis, it must have a <em>maximum</em> that is a <em>positive value of y</em>.

__

<h3>c.</h3>

The graph of a parabola is symmetrical about its vertex. That means points on the same horizontal line are the same distance from the line of symmetry, which must go through the vertex. The x-coordinate of the vertex will be the x-coordinate of the midpoint between the two x-intercepts:

  x = (-2 +5)/2 = 3/2

The x-coordinate of the vertex is x = 1.5.

______

<em>Additional comment</em>

The attachment shows a table with three evenly-spaced points on the curve. The calculations show first differences (d1) and second differences (d2). You can see that the sign of the second diffference is negative, in agreement with the given conditions.

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