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Mathematics

2 answers:

Dovator [93]2 years ago

8 0

Choice 1 is the answer. sources: logic

GaryK [48]2 years ago

6 0

Y= 40 x is the answer, hope this helped.

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The conditional relative frequency table was calculated by row using data from a survey of one station’s television programming.

masya89 [10]

Answer-

The correct option would be-

Given that the program was targeted at adults, there is a 37.5% chance that it was recorded.

Solution-

We know that, probability of A given that B is,

$P(A|B)=\dfrac{P(A\ \cup\ B)}{P(B)}$

From the table,

$P(\text{Recorded})=0.417\\\\P(\text{Adult}) = 1\\\\P(\text{Recorded}\ |\ \text{Adult})=0.375$

Probability that the program was recorded given that the targeted audiences were adults is,

$P(\text{Recorded}\ |\ \text{Adult})=\dfrac{P(\text{Recorded}\ \cup\ \text{Adult})}{P(\text{Adult})}$

$\dfrac{0.375}{1}=0.375=37.5\%$

Probability that the targeted audiences were adults given that the program was recorded is,

$P(\text{Adult}\ |\ \text{Recorded})=\dfrac{P(\text{Adult}\ \cup\ \text{Recorded})}{P(\text{Recorded})}$

$\dfrac{0.375}{0.417}=0.899=89.9\%$

Therefore, the first option "Given that the program was targeted at adults, there is a 37.5% chance that it was recorded." is correct

6 0

2 years ago

Read 2 more answers

The sum of a rational number and an irrational number?

Semenov [28]

Answer:

Is irrational

Step-by-step explanation:

Let $r$ be a rational number, and $i$ be an irrational number. If their sum were rational, say $q$ , then we'd have

$r+i=q \iff i=q-r$

but $q-r$ is the difference between two rational numbers, and thus a rational number. But it also equals $i$ , which is irrational by hypothesis. Since we have a contradiction, we conclude that the sum of a rational and an irrational can't be rational.