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Romashka [77]
3 years ago
6

Which series are neither arithmetic nor geometric? Choose all that apply.

Mathematics
1 answer:
AfilCa [17]3 years ago
3 0
The middle two. An arithmetic series is when something is added over and over again. Geometric is the same except multiplication. For the first one, it only adds 3. For thr last one, it multiplies by -3. For the middle two, I can't seem to find a pattern.
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A dog that weighs 15 pounds should eat 2 1/8 cups of a certain type of dog food per day. How much of the same type of dog food s
Marianna [84]

Answer:

289/60

Step-by-step explanation:

8 0
3 years ago
Find the sum of (8a + 2b - 4)
Svetradugi [14.3K]

Answer:

There is really no answer to this because this is the furtherest you can go to simplify this expression. I can help solve it if you give me more information, or you tell me what the value of a and b is so I can solve it.

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4 0
3 years ago
Read 2 more answers
Find two numbers that have a sum of -2 and a product of -48 (please show work if possible)​
andreev551 [17]

Answer: -8 and 6

Step-by-step explanation:

factors of 48: 1,2,4,6,8,12,24,48

1 x 48

2 x 24

4 x 12

6 x 8

for a negative product, one of the factors must be negative and the other positive.

for two number to have a sum of -2, the greater number must be the negative number, and both numbers should have be two values apart (ex. 6 and 8, 3 and 5, 12 and 14, etc.). In this case, 8 would have to be negative whereas 6 will be left positive.

and then we check:

-8 x 6 = 48

-8 + 6 = -2

5 0
3 years ago
Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang
Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population standard deviation is:

CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}

The information provided is:

<em>n</em> = 26

<em>s</em> = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652

\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}

     =\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

3 0
3 years ago
WILL GIVE BRAINLIEST
castortr0y [4]

3. f(-6) = 12+1 =13


 f(-2) = 4+1 = 5


f(0) =1


Range {1,5,13}


4.  f(-2) = (-2)^3+1 =-7


  f(-1) = (-1)^2 +1 =0


f(3) = (3)^3 +1 = 28


Range = {-7,0,28}


5.the sequence is arithmetic


d= -11+19 = 8


an = a1 + d(n-1)


an = -19 +8(n-1)


6.l =w+5


a =l*w


a(w) =(w+5) * w


a(w)= w^2 +5w


f(w) = w^2 +5w


f(8) = 8^2 +5(8)


f(8) = 64 +40


f(8) =104 in^2



6 0
3 years ago
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