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levacccp [35]
3 years ago
10

Which pair of angles are corresponding? 1 and 3 1 and 4 1 and 5 1 and 8

Mathematics
2 answers:
Marrrta [24]3 years ago
5 0

I can't see where the one is bur if its on the top left it corresponds with 5 then

ella [17]3 years ago
3 0

Answer:

Assuming angle 1 is above angle 3 then the answer is 5

Step-by-step explanation:

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A ship leaves port at 10 miles per hour, with a heading of N 35° W. There is a warning buoy located 5 miles directly north of th
Leno4ka [110]

The value of the angle subtended by the distance of the buoy from the

port is given by sine and cosine rule.

  • The bearing of the buoy from the is approximately <u>307.35°</u>

Reasons:

Location from which the ship sails = Port

The speed of the ship = 10 mph

Direction of the ship = N35°W

Location of the warning buoy = 5 miles north of the port

Required: The bearing of the warning buoy from the ship after 7.5 hours.

Solution:

The distance travelled by the ship = 7.5 hours × 10 mph = 75 miles

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Where;

a = The distance between the ship and the buoy

b = The distance between the ship and the port = 75 miles

c = The distance between the buoy and the port = 5 miles

Angle ∠A = The angle between the ship and the buoy = The bearing of the ship = 35°

Which gives;

a = √(75² + 5² - 2 × 75 × 5 × cos(35°))

By sine rule, we have;

\displaystyle \frac{a}{sin(A)} = \mathbf{ \frac{b}{sin(B)}}

Therefore;

\displaystyle sin(B)= \frac{b \cdot sin(A)}{a}

Which gives;

\displaystyle sin(B) = \mathbf{\frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }}

\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx 37.32^{\circ}

Similarly, we can get;

\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx \mathbf{ 142.68^{\circ}}

The angle subtended by the distance of the buoy from the port, <em>C</em> is therefore;

C ≈ 180° - 142.68° - 35° ≈ 2.32°

By alternate interior angles, we have;

The bearing of the warning buoy as seen from the ship is therefore;

Bearing of buoy ≈ 270° + 35° + 2.32° ≈ <u>307.35°</u>

Learn more about bearing in mathematics here:

brainly.com/question/23427938

5 0
2 years ago
a chef has 5 blocks of butter. Each weights 1 pound. she cuts each block into fourths. how many 1/4 pound pieces of butter does
lianna [129]
The answer would be 20 because you have 5 blocks that are cut into 1/4. It doesn't say anything about any of the pieces disappearing or being used yet so you multiply 4*5 and then you get the answer.
8 0
3 years ago
Find the coordinates of the image of a triangle with vertices. Need help.
ad-work [718]
ANSWER

D. A'(-5,0), B'(0,9) and (2,6)

EXPLANATION

The coordinates of triangle ABC are A(0,-5), B(-9,0) and C(-6,2).

A rotation of 90° clockwise about the origin has the mapping,

(x,y)\to (y,-x)

Therefore the image triangle has vertices

A'(-5,0), B'(0,9) and C'(2,6)

The correct choice is D.
6 0
3 years ago
Pls answer quick I will give brainliest
eimsori [14]

Answer:

EBC and CBF are supplementary.

EBD=66

Step-by-step explanation:

Since vertical angles are congruent, ABE=CBF

ABE=40-x

40-x + 6x-30=90

5x+10=90

5x=80

x=16

16(6)-30=66

6 0
3 years ago
A 24 inch piece of board was cut from the end of a 120 inch long board. The larger piece was then cut in half.
mars1129 [50]
I believe the answer is C
4 0
2 years ago
Read 2 more answers
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