I believe it's Line y=-x+2 and y=3x+1 intersect the y-axis. From what I've gathered, they are parallel lines, and both are set on the y-axis.
Answer:
Explanation has been given below
Step-by-step explanation:
a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.
probability distribution function is F(t)=n*exp(-n*t).
reference to any kth packet and the (k-1)th packet
the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)
b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)
probability of fourth call within t=5 seconds is =
that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.
c) number of calls/rate = 4/n = 4 seconds
The answer is 1.5 bc 0.75 times 2 since it’s the midpoint
20m ^2
Explanation:
The top part be be cut into 2 2•2 triangles. A = 4 for both of them
And the rest is a 4•4 square, so A = 16.
4 + 16 = 20
Hope this helps!
Answer: Option B.
Step-by-step explanation:
In the graph we can see the graph of a quadratic equation (from this we could conclude that the graph will not change the current direction for the arms, so the arms will keep going down), and we also can see that as x increases in absolute value, the value of y decreases.
Then we could conclude that as IxI is really big, we will have that f(x) goes to minus infinity
x -->∞, f(x) --> -∞
x--> -∞, f(x) --> -∞
Then the correct option is B
