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Aliun [14]
4 years ago
7

1/4 (20x+8)+3=0 show work

Mathematics
2 answers:
topjm [15]4 years ago
6 0
So, you need to do the same operation to each side.
Start out by subtracting 3 from each side
1/4 (20x+8) = -3
Then, multiply both sides by 4
40x+8 = -12
Then, subtract 8 from each side
40x = -20
divide both sides by 40 and you get
x=-1/2

Hope this helped!
astra-53 [7]4 years ago
6 0
The first thing you should do is distribute 1/4 into (20x+8). You should do this first because of the order of operations:

Parenthesis
Exponent
Multiplication
Division
Addition
Subtraction

5x+2+3=0

Add 2 and 3 together

5x+5=0

Subtract 5 from each side.

5x=-5

Finally, divide each side by 5

x=-1

To check our answer, substitute -1 in as x

1/4(20(-1)+8)+3=0
1/4(-20+8)+3=0
1/4(-12)+3=0
-3+3=0
0=0

x=-1

Hope this helped! Tell me if you have any other questions! :)
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3 0
3 years ago
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Please help which property is illustrated by this example (3 . 2) . 6 = 3 . (2 . 6)
Sunny_sXe [5.5K]
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7 0
3 years ago
A bird has a mass of 26 g and perches in the middle of a stretched telephone line. (a) Show that the tension in the line can be
Semmy [17]

Answer:

a) is demonstrated below, b) T=1.462N, c) T=14.6N

Step-by-step explanation:

a) Refer to the attached diagram.

Since the bird is standing in the middle of the line and each half is a straight line, Ta=Tb, so we will call the tension T=Ta=Tb and Tay=Tby

By trigonometry Tay=Ta·Sinθ

Since the system is in equilibrium W=Tay+Tby then:

W=2·Tay=2·Ta·Sinθ=2·T·Sinθ

Since W=mg, being m the mass of the bird and g, gravity:

mg=2TSin\theta

Isolating T, we demonstrate that

T=\frac{mg}{2Sin\theta}

b) Replacing θ=5º, m=0.026kg and g=9.8m/s² in the last equation, we can get the tension in Newtons:

T=\frac{0.026*9.8}{2Sin5}=1.462N

c) With θ=0.5º

T=\frac{0.026*9.8}{2Sin0.5}=14.6N

7 0
3 years ago
The polygons in each pair are similar find the scale factor smaller figure to the larger
Delvig [45]

Answer:

smaller figure/larger figure = ½

Step-by-step explanation:

The scale factor = any of the side length of the smaller figure / the corresponding side length of the larger figure

Side length of smaller figure = 3

Corresponding sides length of larger figure = 6

Scale factor = smaller figure/larger figure = 3/6

Simplify

Scale factor = smaller figure/larger figure = ½

7 0
3 years ago
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