5^2+(-2)^2=29
magnitude=(29)^(1/2)=around 5.3852
Let me try . . .
When two lines intersect, they form four (4) angles, all at the same point.
There are two pairs of angles that DON't share a side, and a bunch of other
ones that do share sides. A pair of angles that DON't share a side are called
a pair of "vertical angles".
A pair of vertical angles are equal, but this problem isn't even asking you about
that; it's just asking you to find a pair of vertical angles.
Since you and I are not sitting together at the same table, I can't point to
the drawing and point out different angles to you. You just have to go
through the choices, and find a choice where both angles are formed from
the same two lines.
The first choice (KRE and ERT) is no good, because KR, RE, and RT
are parts of three different lines.
Check out the other 3 choices, and you're sure to find the only one where
both angles are formed by the same two lines.
Answer:
15m +31
Step-by-step explanation:
5(3m+7) - 4 = 15m + 35 - 4 = 15m +31
Answer:
5
Step-by-step explanation:
This is a special right triangle: 5, 12, 13
Or you can solve using the Pythagorean Theorem (a^2+b^2=c^)
--> 13^2-12^2=b^2
-->169-144=b^2
-->25=b^2
b=5
