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DiKsa [7]
3 years ago
8

Write chemical formulas for the following molecular compounds: (a) phosphorus tribromide, (b) dinitrogen tetrafluoride, (c) xeno

n tetroxide, (d) selenium trioxide.
Chemistry
1 answer:
kupik [55]3 years ago
4 0

Answer and Explanation:

(a) Phosphorus tribromide : The chemical formula for phosphorus tribromide is  PBr_3

(b) Dintrogen tetrafluoride : The chemical formula for dinitrogen tetrafluoride is F_4N_2

(C) Xenon oxide : the chemical formula for xenon oxide is XeO_4

(D) Selenium trioxide ; the chemical formula for selenium trioxide is SeO_3

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How does relative-age dating help scientists learn about fossils and the age of the earth?
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Explanation:

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8 0
4 years ago
calculate the freezing point of 3.46 gram of a compound X in 160 gram of benzene when a separate sample of X was vaporized it's
Temka [501]

Answer: The freezing point of 3.46 gram of a compound X in 160 gram of benzene is 4.38^0C

Explanation:

The relation of density and molar mass is:

d=\frac{PM}{RT}

where

d = density = 3.27 g/ L

P = pressure of the gas  = 773 torr = 1.02 atm   (760 torr = 1atm)

M = molar mass of the gas  = ?

T = temperature of the gas = 116^0C=(116+273)K=389K

R = gas constant  = 0.0821Latm/Kmol

M=\frac{dRT}{P}=\frac{3.27g/L\times 0.0821Latm/Kmol\times 389K}{1.02atm}=102.3g/mol

The relation of depression in freezing point with molality:

\Delta T_f=k_f\times m

\Delta T_f = depression in freezing point = T_f^0-T_f = 5.45-T_f

k_f = freezing point constant  = 5.1

m = molality = \frac{\text {moles of X}}{\text {weight of solvent in kg}}=\frac{3.46\times 1000}{102.3\times 160}=0.21

5.45-T_f=5.1\times 0.21

T_f=4.38^0C

Thus the freezing point of 3.46 gram of a compound X in 160 gram of benzene is 4.38^0C

5 0
3 years ago
Which gas will move the slowest of the folowing neon, fluorine, oxygn or nitrogen
Mamont248 [21]

Answer:

oxygeon

Explanation:

5 0
4 years ago
Read 2 more answers
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