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Angelina_Jolie [31]
3 years ago
6

Favorable adaptations build up in a population over many generations due to long-term environmental change. What is the most lik

ely result of this process?
Chemistry
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

<em>The most likely result of this change is the mutation and modification of body parts, properties, and functions to accommodate this change.</em>

Explanation:

When there is a long-term change in an environment, animals develop favorable adaptation over generations to cope with this change. The most likely result of this change is the mutation and modification of body parts, properties, and functions to accommodate this change. A favorable adaptation will lead to the population thriving in this environment even if others die out due to their inability to adapt to these environment. An example is the peppered moth whose black variant now exceeds its white variant due to its ability to blend well unseen on the bark of a pollution darkened tree. The adaptation was necessary to cope with the change in their habitat caused by industrialization.    

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7. How many liters of NH3, at STP will react with 10.6 g O2 to form NO2 and water? 4NH3(g) + 7O2(g) → 4NO2(g) + 6H2O(g) *
Alexus [3.1K]

7) Answer is: c. 4.24 L.

Balanced chemical reaction: 4NH₃(g) + 7O₂(g) → 4NO₂(g) + 6H₂O(g).

m(O₂) = 10.6 g; mass of oxygen.

n(O₂) = m(O₂) ÷ M(O₂).

n(O₂) = 10.6 g ÷ 32 g/mol.

n(O₂) = 0.33 mol; amount of oxygen.

Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).

At STP one mole of gas occupies 22.4 liters of volume.

V(O₂) = n(O₂) · Vm.

V(O₂) = 0.33 mol · 22.4 L/mol.

V(O₂) = 7.42 L; volume of oxygen.

From balanced chemical reaction: n(O₂) : n(NH₃) = 7 : 4.

n(NH₃) = 4 · 0.33 mol ÷ 7.

n(NH₃) = 0.188 mol; amount of ammonia.

V(NH₃) = 0.188 mol · 22.4 L/mol.

V(NH₃) = 4.24 L.

8) Answer is: a. 3.7 g.

Balanced chemical reaction: P₄(g) + 6H₂(g) → 4PH₃(g).

m(P₄) = 3.4 g; mass of phosphorous.

n(P₄) = m(P₄) ÷ M(P₄).

n(P₄) = 3.4 g ÷ 123.9 g/mol.

n(P₄) = 0.0274 mol; limiting reactant.

n(H₂) = 4 g ÷ 2 g/mol.

n(H₂) = 2 mol; amount of hydrogen.

From balanced chemical reaction: n(P₄) : n(PH₃) = 1 : 4.

n(PH₃) = 4 · 0.0274 mol.

n(PH₃) = 0.1096 mol.

m(PH₃) = 0.1096 mol · 34 g/mol.

m(PH₃) = 3.726 g.

9) Answer is: d. Percent yield is the ratio of theoretical yield to actual yield expressed as a percent.

Percent yield = actual yield / theoretical yield.

Theoretical yield is the maximum amount of product that can be produced from limiting reactant and actual yield is a product that is obtained by experimentation.

For example:

the percent yield = 250 g ÷ 294.24 g · 100%.

the percent yield = 84.5 %.

3 0
3 years ago
HELP PLZ ASAP... I'M CONFUSED :(
Snowcat [4.5K]
D. In forward-biased setup, large numbers of charge carriers will be pulled across the junctions and result in a large current
6 0
3 years ago
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Calculate the value of ka for acetylsalicylic acid
lianna [129]

The value of Ka for acetylsalicylic acid will be calculated as Ka=(x+a)²/x.

<h3>What is Ka?</h3>

Ka is known by the name of acid dissociation constant and for weak acid HA at equilibrium Ka will be calculated as:

Ka = [H⁺][A⁻] / [HA]

Chemical equation with ICE table for the acetylsalicylic acid will be shown as:

                  C₉H₈O₄(aq)  +  H₂O(l)  ⇄  C₉H₇O₄(aq)  +  H₃O⁺(aq)

Initial:                 x                                        0                     0

Change:            -a                                        +a                   +a

Equilibrium:      x-a                                      x+a                 x+a

So, Ka for acetylsalicylic acid will be calculated by putting values on the above equation as:

Ka = [x+a][x+a] / [x-a]

Value of a is negligible as compared to the value of x of acetylsalicylic acid so the term x-a becomes x and equation will be written as:

Ka = (x+a)² / x

By knowing the all values of concentration we can calculate the value of Ka.

Hence Ka value for acetylsalicylic acid will be calculated by using the formula as Ka = (x+a)² / x.

To know more about Ka, visit the below link:

brainly.com/question/26998

#SPJ4

5 0
2 years ago
The concentration of H30 in your swimming pool is 4 x 10^-5 M. What is the pH of your pool? O a.-4.4 Ob.4.4 Oc. 0.00004 O d.-0.6
mariarad [96]

Answer:

b. 4.4

Explanation:

pH is related to the concentration of H₃O⁺ through the following equation:

pH = -log([H₃O⁺]) = -log(4 x 10⁻⁵)

pH = 4.4

8 0
4 years ago
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Basile [38]

Answer:allow for greater chances for a sentinel event

Explanation:

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3 years ago
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