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Karolina [17]
3 years ago
9

X is a normally distributed random variable with a mean of 8 and a standard deviation of 4. the probability that x is between 1.

48 and 15.56 is:
Mathematics
1 answer:
Vikentia [17]3 years ago
8 0
The probability is .919
I used normCdf(1.48,15.56,8,4). Or normCdf(-1.63,1.89,0,1) if you standardize your numbers
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When sizes of pizzas are quoted in inches, the number quoted is the diameter of the pizza. A restaurant advertises an 8-inch “pe
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Answer:

yes because if they want a bigger pizza or more they can just buy 2 eight inch pizza

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8 0
2 years ago
Assume a normal distribution and that the average phone call in a certain town lasted 4 min, with a standard deviation of 1 min.
olya-2409 [2.1K]

SOLUTION

The mean is 4min

standard deviation is 1min

the z score is

z=\frac{x-\bar{x}}{\sigma}

where

\begin{gathered} x=3 \\ \bar{x}=4 \\ \sigma=1 \end{gathered}

then we have

\begin{gathered} z=\frac{3-4}{1}=\frac{-1}{1}=-1 \\ z=-1 \end{gathered}

The probability the call lasted less than 3 min will be

Therefore, the probability that (z < -1 ) is

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4 0
1 year ago
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6 0
3 years ago
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evablogger [386]

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Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A line segment has endpoints A(4, 8) and B(2, 10). The point M is the midpoint of AB. What is an equation of a line perpendicula
Vera_Pavlovna [14]
I)

The Midpoint M of the line segment AB is found using the Midpoint formula:

M=( \frac{4+2}{2} , \frac{8+10}{2})=(3, 9)

ii)

the slope of the line through A and B is found by the slope formula:

m= \frac{y_1-y_2}{x_2-x_1}= \frac{10-8}{2-4}= \frac{2}{-2}=-1

iii)

the product of the slopes of 2 perpendicular lines is -1, so the slope of the line perpendicular to the line through A and B is -1/(-1)=1

iv) 

the equation of the line with slope 1, which contains point M(3, 9) is found by the slope point form equation of a line:

y-9=1(x-3)

y-9=x-3

y=x+6


Answer: y=x+6

7 0
3 years ago
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