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Soloha48 [4]
4 years ago
10

Which scenarios are examples of physical change?​

Physics
2 answers:
maks197457 [2]4 years ago
4 0

Answer:

As long as the molecular structure does not change, it is a physical change. As stated by someone else, freezing and boiling are good examples. Another

example would be cutting something like an apple or a piece of paper.

Oxana [17]4 years ago
3 0

Answer:

For example: Freezing, boiling, are physical

Explanation:

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An exoplanet is in an elliptical orbit around a distant star. At its closest approach, the exoplanet is 0.540 AU from the star a
atroni [7]

Answer:

0.71121 km/s

Explanation:

v_1 = Velocity of planet initially = 54 km/s

r_1 = Distance from star = 0.54 AU

v_2 = Final velocity of planet

r_2 = Final distance from star = 41 AU

As the angular momentum of the system is conserved

mv_1r_1=mv_2r_2\\\Rightarrow v_1r_1=v_2r_2\\\Rightarrow v_2=\frac{v_1r_1}{r_2}\\\Rightarrow v_2=\frac{54\times 0.54}{41}\\\Rightarrow v_2=0.71121\ km/s

When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.

7 0
3 years ago
an athlete runs 300 m up a hill at a steady speed of 3.0 m/s. She then immediately runs the same distance at 6.0 m/s . What is h
mina [271]

Answer:

4.0 m/s

Explanation:

In the first part of the run, the athlete runs a distance of

d_1 = 300 m

at a speed of

v_1 = 3.0 m/s

So, the time he/she takes is

t_1 = \frac{d_1}{v_1}=\frac{300}{3.0}=100 s

In the second part of the run, the athlete covers an additional distance of

d_2 = 300 m

with a speed

v_2 = 6.0 m/s

So, the time taken in this second part is

t_2 = \frac{d_2}{v_2}=\frac{300}{6.0}=50 s

So, the total distance covered is

d = 300 m + 300 m = 600 m

And the total time taken

t = 100 s + 50 s = 150 s

Therefore, the average speed for the entire trip is

v=\frac{d}{t}=\frac{600}{150}=4.0 m/s

4 0
4 years ago
A screen is placed 1.60 m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40 c
Lunna [17]

Answer:

distance between the two second-order minima is 2.8 cm

Explanation:

Given data

distance = 1.60 m

central maximum = 1.40 cm

first-order diffraction minima = 1.40 cm

to find out

distance between the two second-order minima

solution

we know that fringe width = first-order diffraction minima /2

fringe width = 1.40 /2 = 0.7 cm

and

we know fringe width of first order we calculate slit d

β1 = m1λD/d

d = m1λD/β1

and

fringe width of second order

β2 = m2λD/d

β2 = m2λD / ( m1λD/β1 )

β2 = ( m2 / m1 ) β1

we know the two first-order diffraction minima are separated by 1.40 cm

so

y = 2β2 = 2 ( m2 / m1 ) β1

put here value

y = 2 ( 2 / 1 ) 0.7

y = 2.8 cm

so distance between the two second-order minima is 2.8 cm

6 0
3 years ago
What can you assume has happened if an electron moves to a higher energy level
tresset_1 [31]

The extra energy that the electron suddenly has had to
come from somewhere, so I can assume that one of
two things happened:

either 1).  A photon passed by and the electron absorbed it.

      or 2).  Somebody hooked up a battery or a generator in
such a way that the electron was bathed in a field of electrostatic
potential, and suddenly had the get-up-and-go to jump to a higher
energy level, and possibly even to leave its atom completely and
zip over to a neighbor atom.

7 0
3 years ago
Read 2 more answers
Subduction occurs as a result of:__________
lutik1710 [3]

Answer:

a) Gravity pulling the older and denser lithosphere downward.

Explanation:

Earth's crust is made of plates which float on mantle . Plates are of two types

1 ) oceanic plates which are older and heavier 2 ) continental plates which are lighter . Continents are situated on continental plates. Due to relative motion , oceanic plate, because of its  heavy weight,  goes under lighter continental plate . This is called subduction.  

6 0
3 years ago
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