Newton's 2nd law of motion says
Net force = (mass) x (acceleration)
Plug in the things you know, and you have
80 N = (20 kg) x (acceleration)
Divide each side by (20 kg) :
80N / 20kg = acceleration
acceleration = 4 m/s²
(a) The average velocity of the particle in the time interval t₁=2sec and t₂=3sec is 10 m/s.
(b) The velocity and acceleration at any time t is v = (4ti + j) m/s and a = a = 4i m/s²
(c) The average acceleration in the time interval given in part (a) is 3.98 m/s².
<h3>Position of the particle</h3>
x = at²i + btj
x = 2t²i + tj
<h3>Average velocity, at t₁=2sec and t₂=3sec</h3>
Δv = Δx/Δt
x(2) = 2(2)²i + 2j
x(2) = 8i + 2j
|x(2)| = √(8² + 2²) = 8.246
x(3) = 2(3)²i + 3j
x(3) = 18i + 3j
|x(3)| = √(18² + 3²) = 18.248
Δv = (18.248 - 8.246)/(3 - 2)
Δv = 10 m/s
<h3>Velocity and acceleration at any time, t</h3>
v = dx/dt
v = (4ti + j) m/s
a = dv/dt
a = 4i m/s²
<h3>Average acceleration</h3>
v(2) = 4(2)i + j
v(2) = 8i + j
|v(2)| = 8.06 m/s
v(3) = 4(3)i + j
v(3) = 12i + j
|v(3)| = 12.04 m/s
a = (12.04 - 8.06)/(3 - 2)
a = 3.98 m/s²
Learn more about average acceleration here: brainly.com/question/104491
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Answer:
v = 7671.57 m/s
T = 1.55 hours
Explanation:
mass of Earth, M = 6 x 10^24 kg
Radius of earth, R = 6400 km = 6.4 x 10^6 m
height, h = 400 km
Velocity is given by
where, G be the universal gravitational constant.
G = 6.657 x 10^-11 Nm^2/kg^2
v = 7671.57 m/s
Let T b the period
T = 5566.53 second
T = 1.55 hours
Answer:
Option D (N/A-m)(m)(m/s)
Explanation:
(N/A-m)(m)(m/s) is the required dimensional analysis for calculation of emi
Answer:
yes
Explanation:
When all of the molecules (or atoms) in a system stop moving completely, that's as cold as they can get
