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Archy [21]
3 years ago
11

Why is the use of scientific names important in biology?

Physics
1 answer:
Dafna11 [192]3 years ago
7 0
Scientifc names are important because they allow people around the world to communicate accurately about animal species.
You might be interested in
Light of wavelength 550nm in air is found to travel at 1.96
Sedaia [141]

Answer:

ν = 5.45 x 10¹⁴ Hz

Explanation:

given,

wavelength of light = 550 nm

                                = 550 x 10⁻⁹ m

speed of light = 1.96 x 10⁸ m/s

speed of sound = 3 x 10⁸ m/s

frequency of the light = ?

we know.

v = \nu \lambda

frequency of the light in the liquid is same as the frequency of the light in the air.

 ν is the frequency of light

\nu = \dfrac{v}{\lambda}

\nu = \dfrac{3\times 10^{8}}{550\times 10^{-9}}

    ν = 5.45 x 10¹⁴ Hz

Hence, the frequency of light in the liquid is equal to ν = 5.45 x 10¹⁴ Hz

8 0
4 years ago
Noah drops a rock with a density of 1.73 g/cm3 into a pond. Will the rock float or sink? Explain your answer
stealth61 [152]

Answer:

Sink

Explanation:

Water has a density of 1 g/cm³.  Since the density of the rock is greater than the density of water, the rock will sink.

4 0
3 years ago
Read 2 more answers
If the mass of an object on Earth is 18 grams, what would the mass of the same object be on the Moon?
Tanya [424]

Answer:18 grams

Explanation:

The mass of an object doesn't change,it is the same everywhere irrespective of it location,therefore if the mass of an object in earth is 18 grams, the mass of the object in the moon will also be 18 grams

4 0
3 years ago
Suppose you wanted to use a non-reflecting layer for radar waves to make an aircraft invisible. What would the thickness of the
Xelga [282]

Answer:

the thickness of the film for destructive interference is 1 cm

Explanation:

We can assume that the radar wave penetrates the layer and is reflected in the inner part of it, giving rise to an interference phenomenon of the two reflected rays, we must be careful that the ray has a phase change when

* the wave passes from the air to the film with a higher refractive index

* the wavelength inside the film changes by the refractive index

         λ = λ₀ / n

so the ratio for destructive interference is

            2 n t = m λ

            t = m λ / 2n

indicate that the wavelength λ = 2 cm, suppose that the interference occurs for m = 1, therefore it is thickness

            t = 1 2/2 n

            t = 1 / n

where n is the index of refraction of the anti-reflective layer. As they tell us not to take into account the change in wavelength when penetrating the film n = 1

            t = 1 cm

So the thickness of the film for destructive interference is 1 cm

8 0
3 years ago
Let's apply Snell's law to the refraction of light across a water–air interface. Suppose you kneel beside the fishpond in your b
Nataliya [291]

Answer:

The angle of refraction is 41.68°.

Explanation:

The refractive index for water is n_2 = 1.333, and for air n_1 = 1.00: the angle of light with the normal is 90^o-60^o = 30^o; therefore Snell's law gives

n_1sin(\theta_1)= n_2sin(\theta_2)

1.00*sin(\theta_1) = 1.33 sin(30^o)

sin (\theta_1) = \dfrac{1.33sin(30^o)}{1.00}

sin (\theta_1) = 0.665

\theta _1 = sin^{-1}(0.665)

\boxed{\theta_1 = 41.68^o}

4 0
3 years ago
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