Let's see what variables we've got first. Hmmm. We have:
Displacement, d = 28 m
Time taken, t = 11 s
Initial velocity, u = 0 m/s (at rest)
And now we need to find the final velocity, v. Among the 4 (or 5) equations of motions, there's no equation that will let us simply plug in the values and give an answer sigh. But fear not! We'll do it in steps.
I'm going to pick one of the motion equation to find more information:

I know everything except for a in this one, so I I'll use this! After plugging in values, I get a = 0.4628 m/s^2.
Now I'm going to use another motion equation that has v in it because that needs to be solved!

Now I know everything except dial velocity v. Nice!
v = 0 + (0.4628)(11)
(a) We must first look at the formulas of the velocities of each toy car. v1 =
-4.2 + 2.60t. v2 = 5.20. When the two cars have equal speed, then
v1 = v2
-4.2 + 2.60t = 5.20
2.60t = 9.40
t = 3.62 s
(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.
(c) The two cars will pass each other when their positions are equal.
x1 = 13.5 - 4.2t + 0.5*2.60t^2
x2 = 8.5 + 5.20t
x1 = x2
13.5 - 4.2t + 1.30t^2 = 8.5 + 5.20t
1.30t^2 - 9.40t + 5.0 = 0
t = 6.65s or t = 0.58 s
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A. 20m/s because the unit for velocity is m/s
Answer:
I=
Explanation:
We are given that
Mass of rod=M
Length of rod=L
Mass of hoop=M
Radius of hoop=R
We have to find the moment of inertia I of the pendulum about pivot depicted at the left end of the slid rod.
Moment of inertia of rod about center of mass=
Moment of inertia of hoop about center of mass=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Answer:
Φ= 17 N•m²•C⁻¹
Explanation:
Gauss's Law states that electric flux equals the surface integral of E•dA. But since we are given all the variables as finite values, we can simplify it into EAcosφ.
-E is given as 95N/C
-A is simply (.4)(.6)=.24m²
-φ is the angle between the E field/vector and the normal/perpendicular vector to the surface. We know that E makes a 20° to the surface here, so the angle φ=(90-20)°=70°. So the E vector makes a 70° angle to the normal of the surface. (I can see this portion as being the point of confusion, as it was for me at first.)
With all that we can say that the flux Φ is:
Φ=(95)(0.24)(cos[70°])=17.4384... N•m²•C⁻¹
I'll approximate to 2 sigfigs in my answer, since that'd be the technical answer.
*I believe V/m are also correct units for electric flux.