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ZanzabumX [31]
4 years ago
14

I need help with this?

Mathematics
1 answer:
Masja [62]4 years ago
4 0

since u know that there is 60 minutes in a hour do 60 times 3 and u will get 180.then do 180 divided by28 and u will get ur final answer which is 6 minutes and 12 seconds


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A doctor prescribes 150 milligrams of a therapeutic drug that decays by about 15% each hour. To the nearest hour, what is the ha
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Answer:

4 hours

Step-by-step explanation:

The amount remaining at the end of each hour is 0.85 of the amount at the start of the hour. You want to find the exponent such that ...

... 0.85^x = 0.5 . . . . . x = the number of hours until half is left

... x·log(0.85) = log(0.5) . . . . . take the log to turn it to a linear equation

... x = log(0.5)/log(0.85) ≈ 4.265024

Rounded to the nearest  hour, x = 4.

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What is the area of the 3.1 by 1.4 rectangle?
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Answer: 4.34

Step-by-step explanation:

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What would the missing coordinate be if there was an inverse relationship between points (12,3) and (x,9)
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4.

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5 0
3 years ago
A set of equations is given below:
miv72 [106K]
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3 years ago
Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am
zheka24 [161]

SOLUTION

We have been given the equation of the decay as

\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}

So we are looking for the time

Plugging the values into the equation, we have

\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}

Taking Ln of both sides, we have

\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}

Hence the answer is 4308 to the nearest year

8 0
1 year ago
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