Ask question

Ask question

All categories

3 years ago

12

A hexagonal pyramid is cut by a plane as shown in the diagram. What is the shape of the resulting cross section?

2 answers:

tiny-mole [99]3 years ago

8 0

Cross section is a surface that is exposed after slicing or making a cut through an object. If a hexagonal pyramid is cut horizontally then the cross section should be an hexagon as well since the base is a hexagon. However, when it is cut vertically the resulting shape would be a triangle.

Mama L [17]3 years ago

4 0

a parallelogram

is the answer

You might be interested in

If integral 1 to 5 f(x)dx =36/15 what is the value of integral from 5 to 1 f(x)dx?<br><br><br>

fredd [130]

Answer:

-36/15

Step-by-step explanation:

If the indefinite integral of f(x)dx is F(x), then your integral from 1 to 5 is ...

F(5) -F(1) = 36/15

The integral in the reverse direction is ...

F(1) -F(5) = -(F(5) -F(1)) = -36/15

6 0

3 years ago

Answer the following question regarding the table below.

sveta [45]

<u>40 is shown 3 times, 41 is shown 3 times, 42 is shown 3 times, and 43 is shown 3 times. </u>

I would put as the answer that <u>all the numbers are equally shown the same amount of times. </u>

4 0

3 years ago

Read 2 more answers

What is the slope of the line on the graph?<br><br> Enter your answer in the box.

Olenka [21]

Look at points (0, -1) and (1, 5).

m = (y2 - y1)/(x2 - x1) = (5 - (-1))/(1 - 0) = 6/1 = 6

Slope = 6

Answer: 6

6 0

3 years ago

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

3 0

3 years ago

This person has been spamming me so I know they’ll read this. Your a really annoying person. All you do is spam useless links an

zmey [24]

Answer:

The same person does that to me and i heard to NOT mess with those link because they can find our address or something

Step-by-step explanation:

4 0

3 years ago