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3 years ago

A hexagonal pyramid is cut by a plane as shown in the diagram. What is the shape of the resulting cross section?

2 answers:

8 0

Cross section is a surface that is exposed after slicing or making a cut through an object. If a hexagonal pyramid is cut horizontally then the cross section should be an hexagon as well since the base is a hexagon. However, when it is cut vertically the resulting shape would be a triangle.

Mama L [17]3 years ago

4 0

a parallelogram

is the answer

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Can someone help me with this please? Thank you!

Finger [1]

Answer:

528 cm²

Step-by-step explanation:

First I would calculate the area of the side rectangles:

20 x 9 = 180 cm²

There are two identical rectangles on both sides so i would x2

180 x 2 = 360 cm²

The area of the middle rectangle:

6 x 20 = 120 cm²

The area of the triangles:

Area of a triangle = (Base x Height)/2

8 x 6 = 48

48 ÷ 2 = 24

There are two identical triangles on the bottom and the top so x2

24 x 2 = 48

Now add all the values up:

360 + 120 + 48 = 528 cm²

I hope this helps!

5 0

2 years ago

A square pyramid is shown. What is the surface area?

ICE Princess25 [194]

Answer:The answer is B

Step-by-step explanation:

first find te height:

1.5/2=0.75 (this will be your "b" of the pythagorean theorem for finding the height)

now do the pythagorean theorem:

a^2+0.75^2=3^2

(height)= 2.905

A= a^2+2a√((a^2/4)+h^2)

a (base edge)= 1.5

h (height)= 2.905

Calculate and you get B as your answer.

Hope this elpsand you get this right!

7 0

3 years ago

Ben has a set of coupons for a video game that costs $39. the coupons are 30% off, 1 game for $19, $10 off, off, and 10% off gam

IRINA_888 [86]

The correct answer is <span>a. {1 game for $19, off, 30% off, $10 off, 10% off games over $40}.

Hope this helps!!
~Kiwi
</span>

4 0

3 years ago

Inquashia took out a 2900 loan for a car the interest on the loan is a 8% compounded monthly how much in total will in Isha and

Shtirlitz [24]

Answer: the total amount after 6 years is 4690

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount of the loan at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount loaned.

From the information given,

P = 2900

r = 8% = 8/100 = 0.08

n = 12 because it was compounded 12 times in a year.

t = 6 years

Therefore,

A = 2900(1 + 0.08/12)^12 × 6

A = 2900(1 + 0.0067)^72

A = 2900(1.0067)^72

A = 4690

8 0

2 years ago

For integers a, b, and c, consider the linear Diophantine equation ax C by D c: Suppose integers x0 and y0 satisfy the equation;

Dmitrij [34]

Answer:

$x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )$

b. x = -8 and y = 4

Step-by-step explanation:

This question is incomplete. I will type the complete question below before giving my solution.

For integers a, b, c, consider the linear Diophantine equation

$ax+by=c$

Suppose integers x0 and yo satisfy the equation; that is,

$ax_0+by_0 = c$

what other values

$x = x_0+h$ and $y=y_0+k$

also satisfy ax + by = c? Formulate a conjecture that answers this question.

Devise some numerical examples to ground your exploration. For example, 6(-3) + 15*2 = 12.

Can you find other integers x and y such that 6x + 15y = 12?

How many other pairs of integers x and y can you find ?

Can you find infinitely many other solutions?

From the Extended Euclidean Algorithm, given any integers a and b, integers s and t can be found such that

$as+bt=gcd(a,b)$

the numbers s and t are not unique, but you only need one pair. Once s and t are found, since we are assuming that gcd(a,b) divides c, there exists an integer k such that gcd(a,b)k = c.

Multiplying as + bt = gcd(a,b) through by k you get

$a(sk) + b(tk) = gcd(a,b)k = c$

So this gives one solution, with x = sk and y = tk.

Now assuming that ax1 + by1 = c is a solution, and ax + by = c is some other solution. Taking the difference between the two, we get

$a(x_1-x) + b(y_1-y)=0$

Therefore,

$a(x_1-x) = b(y-y_1)$

This means that a divides b(y−y1), and therefore a/gcd(a,b) divides y−y1. Hence,

$y = y_1+r(\frac{a}{gcd(a, b)})$ for some integer r. Substituting into the equation

$a(x_1-x)=rb(\frac{a}{gcd(a, b)} )\\gcd(a, b)*a(x_1-x)=rba$

$x = x_1-r(\frac{b}{gcd(a, b)} )$

Thus if ax1 + by1 = c is any solution, then all solutions are of the form

$x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )$

In order to find all integer solutions to 6x + 15y = 12

we first use the Euclidean algorithm to find gcd(15,6); the parenthetical equation is how we will use this equality after we complete the computation.

$15 = 6*2+3\\6=3*2+0$