Hi, hope this helps you. Have a good day. :)
Answer:
A = $5,417.42 (balance of the account)
I = $2,617.42
We are given
P = $754.43
r = 13.6% annual
for a.
A = 150
for b.
A = 300
First, change the interest into effective monthly
i = (1 + 0.136/12)^12 - 1
Solve for i
Next, use the general formula
A = P i ( 1 + i)^n / (1 + 1)^n - 1
Subsitute P, i, and A for a and b.
Then, solve for n for a and b.
Hi there! So, we know that the price of the camera is $84, and the carrying case is 12% of that price. Let's find the cost of the case. To find the cost of the carrying case, all you have to do is multiply the price of the camera by the percentage. 84 * 12% (0.12) is 10.08. The price of the carrying case is $10.08. Let's add that price to the price of the camera. 84 + 10.08 is 94.08. $94.08 is the purchase price, but we're not done. We must add the tax in to find the total price. We can add 100% to the tax rate of 6% to get 106% Adding 100% to the amount of tax helps us get straight to the total price. Multiply that by 94.08. 94.08 * 106% (1.06) is 99.7248 or 99.72 when rounded to the nearest hundredth. There. The total price of the purchase is $99.72.
It wouldn't play or else i would help
Change your fraction to whole by 72×8+1 which is 577 then do 9×9+1 which is 82 then times 577 to 82 which is 47,314
