The given functions of <em>f </em>and <em>g</em>, where;
, 
gives the domain of the functions as the option;
a. All non zero real numbers
<h3>How can the domain of the functions be found?</h3>
The given functions are presented as follows;
The given functions have <em>x²</em> as the denominator, therefore;
The domain of the functions are the possible x-values, which gives;
x² = (-x)² = Positive number
At <em>x </em>= 0, we have;
The domain is therefore;
a. All non zero real numbers
Learn more about the domain and range of a function here:
brainly.com/question/2264373
#SPJ1
Answer:
Problem 1: No
Problem 2: Yes
Step-by-step explanation:
Problem 1:
{(-2, 1), (-2, 3), (0, -3), (1, 4), (3, 1)}
This relation is not a function because there are two y-values, 1 and 3, related to one x-value, -2.
Thus, for a relation to be a function, every x-value must be related to exactly 1 y-value.
Problem 2:
{(0, 2), (3, 4), (-3, -2), (2, 4)}
In this relation, each x-value (domain) has exactly one y-value (range) that it is related to. Therefore, this is a function.
Answer:
Step-by-step explanation:
root(23) - 8 < root(23) - 3 -3 is greater than -8
3 root(62) > 3 root(59) 62 > 59 Since the numbers are positive the roots of the larger number is going to be larger than the roots of the smaller number
-root(50) < - 3
The root of 50 is about 7. - 7 is smaller than - 3. Think money. Would you rather pay 3 dollars for a cup of coffee than 7 dollars for a cup of coffee?
root 15 + 2 < root(65) - 1
root(15) is roughly 4 when 2 is added to it, the result is about 6
root (65) is a touch over 8. When 1 is subtracted the result is about 7.
That's larger than the left side.
Answer:
A. 266
Step-by-step explanation:
Answer:
22/3 i believe
Step-by-step explanation:
