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3 years ago

8

Please help me im stuck on this one :(

2 answers:

fiasKO [112]3 years ago

7 0

I believe it is the third answer choice since it is theonly one which expresses the equation correctlyin alegebra tiles.

Hope this helps (:

AnnyKZ [126]3 years ago

3 0

-x + 8 = 7x + (-8)

Answer should be C. third one

1 negative x tile and 8 positive units tiles on the left;
7 positive x tiles and 8 negative units tiles on the right

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daser333 [38]

Answer:

34,220

Step-by-step explanation:

Because order doesn't matter, but the numbers can't be repeated, we need to find the number of combinations where 3 individual numbers can be chosen out of 60 possible numbers using the binomial coefficient:

$\binom{n}{k}=\frac{n!}{k!(n-k)!}\\ \\\binom{60}{3}=\frac{60!}{3!(60-3)!}\\\\\binom{60}{3}=\frac{60!}{3!(57)!}\\\\\binom{60}{3}=\frac{60*59*58}{3*2*1}\\ \\\binom{60}{3}=34220$

Thus, Elias can make 34,220 unique 3-number codes given 60 different numbers.

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2 years ago

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Answer:

Step-by-step explanation:

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$A=\frac{\pi r^2}{2} \\=\frac{\pi 1^2}{2} \\=6.283m^2$

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$A=a^2=2^2=4m^2\\6.283+4=10.283m^2$

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$A=\frac{ab}{2} \\=\frac{6*2.5}{2} \\=7.5m^2\\7.5*2=15m^2$

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$104-15=89m^2$

3.

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Square

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$36-14.137=21.863m^2$

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