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victus00 [196]
3 years ago
10

A snail moves 1/50 a mile in 5/6 of an hour. If the snail continues at this pace, how far, in miles, does it move in one hour?

Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0
\dfrac{5}{6} \text { of an hour = }   \dfrac{1}{50}  \text { mile}

--------------------------------------------------------------
Find 1/6 hour :
--------------------------------------------------------------
\dfrac{1}{6} \text { of an hour = }   \dfrac{1}{50} \div 5  \text { mile}

\dfrac{1}{6} \text { of an hour = }   \dfrac{1}{50} \times  \dfrac{1}{5}   \text { mile}

\dfrac{1}{6} \text { of an hour = }   \dfrac{1}{250} \text { mile}

--------------------------------------------------------------
Find 6/6 hour ( 1 hour) :
--------------------------------------------------------------
\dfrac{6}{6} \text { of an hour = }   \dfrac{1}{250} \times 6 \text { mile}

\dfrac{6}{6} \text { of an hour = }   \dfrac{6}{250} \text { mile}

\dfrac{6}{6} \text { of an hour = }   \dfrac{3}{125} \text { mile}

--------------------------------------------------------------
Answer: It moves 3/125 mile in an hour.
--------------------------------------------------------------
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Hey there

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(1/2)(3/4) = (3/8) of a cup

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3 0
3 years ago
Stardust the unicorn, covered a distance of 50 miles on his first trip to the forest. On a later trip he travelled 300 miles whi
jok3333 [9.3K]

His new time compared with the old time was increased by factor of 2

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration (m / s²)v = final velocity (m / s)</em>

<em>u = initial velocity (m / s)</em>

<em>t = time taken (s)</em>

<em>d = distance (m)</em>

Let us now tackle the problem!

This problem is about Kinematics.

In this problem we assume that the unicorn is moving at a constant speed so that the acceleration is zero.

<u>Given:</u>

first distance = d₁ = 50 miles

second distance = d₂ = 300 miles

v₂ = 3 v₁

<u>Unknown:</u>

t₂ : t₁ = ?

<u>Solution:</u>

To find his new time , we will use the following formula.

v_2 = 3 v_1

\frac{d_2}{t_2} = 3 \times \frac{d_1}{t_1}

\frac{300}{t_2} = 3 \times \frac{50}{t_1}

\frac{300}{t_2} = \frac{150}{t_1}

t_2 = \frac{300}{150} \times t_1

\large {\boxed {t_2 = 2 \times t_1} }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Sperm , Whale , Travel

8 0
3 years ago
PLEASE ANSWERRRRRRRRRR
mash [69]

Answer: OPTION B.

Step-by-step explanation:

Given the following System of equations:

\left \{ {{3x-5y=19} \atop {x+y=1}} \right.

You can use the Elimination Method to solve it. The steps are:

1. You can mutliply the second equation by -3.

2. Then you must add the equations.

3. Solve for the variable "y".

Then:

\left \{ {{3x-5y=19} \atop {-3x-3y=-3}} \right.\\.....................\\-8y=16\\\\y=\frac{16}{-8}\\\\y=-2

4. Now that you know the value of the variable "y", you must substitute it into any original equation.

5. The final step is to solve for "x" in order to find its value.

Then:

x+(-2)=1\\\\x=1+2\\\\x=3

Therefore, the solution is:

(3,-2)

8 0
3 years ago
What is the x and y intercept for 4x-5y=-20
yuradex [85]
X intercept is when y = 0 so 4x = -20, x=-5 
y intercept when x = 0 so -5y = -20, y=4
7 0
3 years ago
Read 2 more answers
I WILL GIVE BRAINLIEST :)
Triss [41]

Answer: I got 50x+$75 but I’m not too sure for the last step

Step-by-step explanation:

7 0
2 years ago
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