If you shift function f(x) a units right you'll get f(x-a) function.
So if you have f(x) = x², you'll get f(x-10) = (x-10)² - answer B
other formulas:
a units left: f(x+a)
a units up: f(x)+a
a units down: f(x)-a
Step-by-step explanation:
Lets first find the remainder when p(x) is divided by x-2
p(2)=2(2)³+b(2)²+3(2)-5
p(2)=16+4b+6-5
p(2)=4b+17
Now let's find the remainder when q(x) is divided by x-2
q(2)=(2)³+(2)²-4(2)-b
q(2)=8+4-8-b
q(2)=4-b
Now let's equate both of them
4b+17=4-b
4b+b=4-17
5b=-13
b=-13/5 as required
If there are no repeating x values and an x value only goes to <em>one</em><em> </em>y value, then yes, it is a function.