Answer:
10
Step-by-step explanation:
It would be the second graph since the coefficient is negative
The value of θ is 45 degrees as sin45° is equal to 1/√2.
<h3>What is trigonometric equation?</h3>
Trigonometric equation refers to an equation consists of a number of trigonometric ratios whose angle is unknown.
<h3>What is the ranges of trigonometric angle?</h3>
Generally trigonometric angles are represented by θ. while solving equations we get the values of θ ranges from 0 degree to 90 degrees.
Given, 2sin²θ = 1
solving the equation
sin²θ = 1/2
sinθ = 1/√2
we know sin45° has a specific value 1/√2
sinθ = sin 45°
now, θ = 45°
hence, the solution is θ = 45 degrees.
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3ab...when a = 2 and b = 3
(3)(2)(3) = 6(3) = 18
Answer:
Dh/dt = 0.082 ft/min
Step-by-step explanation:
As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of 1 feet and height h = 2 feet.
The volume of a circular cone is:
V(c) = 1/3 * π*r²*h
Then differentiating on both sides of the equation we get:
DV(c)/dt = 1/3* π*r² * Dh/dt (1)
We know that DV(c) / dt is 1 ft³ / 5 min or 1/5 ft³/min
and we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment
By proportion we know
r/h ( at the top of the cone 0,5/ 2) is equal to r/0.5 when water is 1/2 foot deep
Then r/h = 0,5/2 = r/0.5
r = (0,5)*( 0.5) / 2 ⇒ r = 0,125 ft
Then in equation (1) we got
(1/5) / 1/3* π*r² = Dh/dt
Dh/dt = 1/ 5*0.01635
Dh/dt = 0.082 ft/min