To start this question, we should know what is the atomic number of cobalt. The atomic number (the number of protons) of Cobalt is Z =27.
Now, we know that a Cobalt 60 isotope means an isotope of Cobalt whose Atomic Mass is 60
Thus, in a Cobalt 60 isotope, the number of neutrons in the nucleus are .
From the question we know that the given nuclear mass is 59.933820 u.
Now, the mass defect of Cobalt 60 can be easily calculated by adding the masses of the protons and the neutrons as per our calculations and subtracting the given nuclear mass from it.
Thus,
Mass Defect = (Number of Protons Mass of Proton given in the question) + (Number of Neutrons Mass of Neutron given in the question)-59.933820 u
Mass Defect =
Thus, the required Mass Defect is
In eV, the Mass Defect is
Answer:
its 3/5 so you just add the numerator to the numerator and add the denominator to the denominator.
Answer:
Step-by-step explanation:
You can only multiply matrices if the number of columns in the matrix on the left is the same exact number as the number of rows in the matrix to the right of that other matrix.
The matrix on the left, |5 -2 4| has the dimensions
1 x 3 (1 row, 3 columns)
The matrix to its right, |2 7 -3| has the dimensions
1 x 3 (1 row, 3 columns).
Putting those dimensions next to each other in that order:
1 x 3 1 x 3
The bold print 3 and 1 have to be the same number (both 3's or both 1's) in order for the multiplication to work. This doesn't work; it's impossible.
164.00 is your answer
Hope it helps!
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Since there is no distance between the pole and the base of the tower, we can assume that the pole is at the base of the tower.
We can create a right triangles between the pole and its shadow and between the tower and its shadow as shown in the figure. Let
be the height of the tower. Since our triangles are similar the ratio between its sides is going to be proportional, so we can establish a proportion to find
:
We can conclude that the tower is 137.27 meters tall.