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Pachacha [2.7K]

3 years ago

6

The current in the wires of a circuit is 120.0 milliAmps. If the voltage impressed across the ends of the circuit were doubled (

with no change in its resistance), then its new current would be _____ milliAmps.

1 answer:

skad [1K]3 years ago

7 0

Answer:

Its new current will be 240.0milliAmps

Explanation:

According to ohms law,

V = IR

V is the supply voltage in a circuit

I is the current

R is the resistance

If the current in the wires of a circuit is 120.0 milliAmps, the voltage will be:

V1 = 120R1

R1 = V1/120...(1)

If the voltage impressed across the ends of the circuit were doubled (with no change in its resistance),

V2 = 2V1

V2 = IR2

2V1 = IR2

R2 = 2V1/I ... (2)

Since there are no changes in resistance

R1 = R2

Equating 1 and 2, we have:

V1/120 = 2V1/I

1/120 = 2/I

Cross multiplying

I = 2×120

I = 240milliAmps

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Artyom0805 [142]

Answer:

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Explanation:

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