3. Due to the fact that friction is not converted to kinetic energy nor potential energy. The energy is converted into heat energy which is lost and can’t be put back
Answer:
My best friend lol cuz since quarantine i didn't see her
Answer:
He needs 1.53 seconds to stop the car.
Explanation:
Let the mass of the car is 1500 kg
Speed of the car, v = 20.5 m/s
He will not push the car with a force greater than, ![F=2\times 10^4\ N](https://tex.z-dn.net/?f=F%3D2%5Ctimes%2010%5E4%5C%20N)
The impulse delivered to the object is given by the change in momentum as :
![F\times t=mv\\\\t=\dfrac{mv}{F}\\\\t=\dfrac{1500\times 20.5}{2\times 10^4}\\\\t=1.53\ s](https://tex.z-dn.net/?f=F%5Ctimes%20t%3Dmv%5C%5C%5C%5Ct%3D%5Cdfrac%7Bmv%7D%7BF%7D%5C%5C%5C%5Ct%3D%5Cdfrac%7B1500%5Ctimes%2020.5%7D%7B2%5Ctimes%2010%5E4%7D%5C%5C%5C%5Ct%3D1.53%5C%20s)
So, he needs 1.53 seconds to stop the car. Hence, this is the required solution.
As we know that electrostatic force between two charges is given as
![F = \frac{kq_1q_2}{r^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bkq_1q_2%7D%7Br%5E2%7D)
here we know that electrostatic repulsion force is balanced by the gravitational force between them
so here force of attraction due to gravitation is given as
![F_g = 1.98 \times 10^{20} N](https://tex.z-dn.net/?f=F_g%20%3D%201.98%20%5Ctimes%2010%5E%7B20%7D%20N)
here we can assume that both will have equal charge of magnitude "q"
now we have
![1.98 \times 10^{20} = \frac{kq^2}{r^2}](https://tex.z-dn.net/?f=1.98%20%5Ctimes%2010%5E%7B20%7D%20%3D%20%5Cfrac%7Bkq%5E2%7D%7Br%5E2%7D)
![1.98 \times 10^{20} = \frac{(9\times 10^9)(q^2)}{(3.84 \times 10^8)^2}](https://tex.z-dn.net/?f=1.98%20%5Ctimes%2010%5E%7B20%7D%20%3D%20%5Cfrac%7B%289%5Ctimes%2010%5E9%29%28q%5E2%29%7D%7B%283.84%20%5Ctimes%2010%5E8%29%5E2%7D)
![1.98 \times 10^{20} = (6.10 \times 10^{-8}) q^2](https://tex.z-dn.net/?f=1.98%20%5Ctimes%2010%5E%7B20%7D%20%3D%20%286.10%20%5Ctimes%2010%5E%7B-8%7D%29%20q%5E2)
now we have
![q = 5.7 \times 10^{13} C](https://tex.z-dn.net/?f=q%20%3D%205.7%20%5Ctimes%2010%5E%7B13%7D%20C)
I’m pretty sure it just wants you to list the property’s meaning the material and density