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Delvig [45]
3 years ago
8

You weigh 620 N. What would you weigh if the Earth were three times as massive as it is and its radius were four times its prese

nt value? Answer in units of N
Physics
1 answer:
Klio2033 [76]3 years ago
4 0

Answer:

if

Explanation:

weight is the force of gravity on a mass; the force of gravity is

F = G M m/r^2

F is grav force

G is the newtonian gravitational constant = 6.67 x 10^-11 Nm^2/kg^2

M=mass of the earth

m=mass of the object

r= radius of the earth

if the mass of the earth increases by a factor of 6, this will tend to increase the grav force by a factor of 6

if the radius increases by a factor of 5, this will change the grav force by a factor of 1/5^2 = 1/25

the total effect is 6/25 = 0.24; therefore, your weight would be 0.24 * 620N = 149N

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A negatively-charged particle is slowly moving as it enters a region that has a constant magnetic field. If the velocity of the
Anna71 [15]

Answer:

no deflection and net force is zero. Moving in same direction and with same speed

Explanation:

Charge = negative

the angle between the velocity vector and the magnetic field vector is 0°, so the force is given by

F = q v B Sin 0

F = 0

As the force is zero so the charge particle moves with the same velocity and in the same direction.

there is no deflection in the path of negatively charged particle.

7 0
3 years ago
Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?
Hitman42 [59]

The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:

h = \frac{v^{2}}{2g}

<h3>What are perfectly elastic collision?</h3>

Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.

In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.

Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.

Since some of the Kinetic energy is converted to potential energy of the body;

\frac{mv^{2}}{2} = mgh

h = \frac{v^{2}}{2g}

Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.

Learn more about elastic collisions at: brainly.com/question/7694106

7 0
2 years ago
A third wire of the same material has the same length and twice the diameter as the first. How far will it be stretched by the s
leonid [27]

Complete question is;

A force stretches a wire by 0.60 mm. A second wire of the same material has the same cross section and twice the length.

a) How far will it be stretched by the same force?

b) A third wire of the same material has the same length and twice the diameter as the first. How far will it be stretched by the same force?

Answer:

0.15 mm

Explanation:

According to Hooke's Law,

E = Stress(σ)/Strain(ε)

Where E is youngs modulus

Formula for stress is;

Stress(σ) = Force(F)/Area(A)

Formula for strain is;

Strain(ε) = Change in length/original length = (Lf - Li)/Li

We are also told that a second wire of the same material has the same cross section and twice the length.

Thus;

Rearranging Hooke's Law to get the constants on one side, we have;

F/(AE) = ε

Thus from the conditions given;

ε1 = 0.6/Li

ε2 = (Change in length)/(2*Li)

And ε1 = ε2

Thus;

0.6/Li = Change in length/(2*Li)

Li will cancel out and we now have;

Change in length = 2 × 0.6 = 1.2 mm

Finally, we are told A third wire of the same material has the same length and twice the diameter as the first.

Area of a circle;A1 = πd²/4

Now, we are told d is doubled.

Thus, new area of the new circle is;

A2 = π(2d)²/4 = πd²

Rearranging Hooke's Law,we have;

F/A = εE

Since F and E are now constants, we have;

F/E = constant = Aε

Thus;

A1(ε1) = A2(ε2)

A1 = πd²/4

e1 = 0.60/Li

A2 = πd²

e2 = Change in length/Li

Thus;

((πd²/4) × 0.6)/Li = (πd² × Change in length)/ Li

Rearranging, Li and πd² will cancel out to give;

0.6/4 = Change in length

Change in length = 0.15 mm

4 0
3 years ago
You are working with a team to design a better electron microscope. To precisely control the beam of electrons, your team decide
rewona [7]

Answer and Explanation:

(a) The attached image below shows the diagram of a CRT in the helmholtz coils and well labelled with details

(b). The electron will follow a circular path which travels along under constant magnetic field

r = \frac{mV}{qB}

where m = mass of electron, V = velocity of electron, q = charge of the electron and B = magnetic field strength

4 0
3 years ago
Read 2 more answers
Three resistors of 100 W, 3900 W, and 1000 W are connected in series across a 200-V battery. What is the voltage drop across the
Gala2k [10]

Answer:

40 V

Explanation:

 I will assume that  the resistors are

           100 and 3900 and 1000 OHMS    <=====(NOT W)

In series , the resistances add together 100 + 3900 + 1000 = 5000 ohms total

V = IR

I = V / R      so the total current will be   200 v / 5000 ohms = .04 amps

                   this is the current through all of the resistors

      so for the   1000 ohm resistor     V = IR     .04 (1000) = 40 V

7 0
2 years ago
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