Answer:
1.13 mA
Explanation:
Length of wire L = 20.5 cm = 0.205m
Radius of wire r = 2.60/2 = 1.3cm = 0.0130m
Voltage V = 1 × 10³ V
Resistivity of pure silicon p = 2300 Ohms • m
Cross sectional area of the wire
A = pi × r² = pi × (0.013)² = 5.307 × 10 ^-4 m²
Resistance of the material
R = p• L/A
= 2300 • 0.205/5.307 × 10^-4 = 0.888 × 10⁶ Ohms
Using Ohms Law
R = V/ I
I = V/R
I = 10³/0.888 × 10⁶
= 0.001126 A
= 1.13 mA
Answer: d
Explanation:
had the same study island question
Answer:
ANswers
Explanation:
Friction, knetic, and physics
Answer:
8.1345°
Explanation:
We apply 
to the wire to obtain:
#The magnitude of the magnetic force acting on the wire is given by:
#Substitute for 
to obtain:
Solve for 
:
![\theta=sin^{-1}[\frac{IlB}{mg}]](https://tex.z-dn.net/?f=%5Ctheta%3Dsin%5E%7B-1%7D%5B%5Cfrac%7BIlB%7D%7Bmg%7D%5D)
We the substitute the numerical values to calculate the equilibrium angular displacement:
![\theta= sin^{-1}[\frac{0.2A\times0.52m\times 0.040T}{0.003\ kg\times9.8m/s^2}]\\\\=8.1345\textdegree](https://tex.z-dn.net/?f=%5Ctheta%3D%20sin%5E%7B-1%7D%5B%5Cfrac%7B0.2A%5Ctimes0.52m%5Ctimes%200.040T%7D%7B0.003%5C%20kg%5Ctimes9.8m%2Fs%5E2%7D%5D%5C%5C%5C%5C%3D8.1345%5Ctextdegree)
Hence, the equilibrium angular displacement of the wire from vertical if the horizontal magnetic field is 8.1345°
