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Sergeu [11.5K]
3 years ago
15

What is the upper quartile of the data represented in the following box-and-whisker plot?

Mathematics
1 answer:
Gala2k [10]3 years ago
6 0
Answer: The upper quartile is 12.

In a box and whiskers plot, the point on the right edge of the box is called the upper quartile. In this case, that value is 12. It represents the median of the upper half of the set of data.
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An investor wants to save money to purchase real estate. She buys an annuity with monthly payments that earn 5.6% interest, comp
Lena [83]

Answer:

1040

Step-by-step explanation:

just took 65 and mutiply 65$

6 0
3 years ago
Hong rented a truck for one day. There was a base fee of $20.95, and there was an additional charge of 90 cents for each mile dr
Goryan [66]

Answer: Hong drove the truck for 294 miles.

Step-by-step explanation:

Let m represent the number of miles for which he drove the truck.

There was a base fee of $20.95, and there was an additional charge of 90 cents for each mile driven. It means that the expression for the cost of driving the truck for m miles in a day is

20.95 + 0.9m

Hong had to pay $285.55 when he returned the truck. It means that

20.95 + 0.9m = 285.55

0.9m = 285.55 - 20.95

0.9m = 264.6

m = 264.6/0.9

m = 294 miles

5 0
3 years ago
Find the coordinates of the image of a triangle with vertices A(0, – 3), B(3, 0), and
lora16 [44]

Answer:

A'(-3,0), B'(0,-3) and C'(4,7)

Step-by-step explanation:

We are given that the vertices of triangle are A(0,-3), B(3,0) and C(-7,4).

We have to find the coordinates of the image of triangle under a rotation of 90° clockwise about the origin.

90° clockwise about the origin

Rule:(x,y)\rightarrow (y,-x)

Using the rule

The coordinates of A'

A(0,-3)\rightarrow A'(-3,0)

The coordinates of B'

B(3,0)\rightarrow B'(0,-3)

The coordinates of C'

C(-7,4)\rightarrow C'(4,7)

Hence, the vertices of image of triangle is given by

A'(-3,0), B'(0,-3) and C'(4,7)

8 0
2 years ago
Find lim h→0 f(2+h)-f(2)/h if f(x)=x^2+x+1
bekas [8.4K]

Answer:

5

Step-by-step explanation:

\displaystyle \lim_{h \to 0} \frac{f(2+h)-f(2)}{h}

\displaystyle\lim_{h \to 0} \frac{(2+h)^2 + 2 + h + 1 - 2^2 - 2 - 1}{h}

\displaystyle\lim_{h \to 0} \frac{4 + 4h + h^2 + h - 4}{h}

\displaystyle\lim_{h \to 0} \frac{h^2 + 5h}{h}

\displaystyle\lim_{h \to 0} h + 5

= 5

8 0
2 years ago
-4i+ 3i= i- 8+ 3i- 12
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

-4i+3i=i-8+3i-12

-i=4i-20

20=4i+i

20=5i

20/5=i

4=i

4 0
2 years ago
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