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3 years ago

7

The price of a gallon of unleaded gas has dropped to $2.83 today. Yesterday's price was $2.90 . Find the percentage decrease. Ro

und your answer to the nearest tenth of a percent.

2 answers:

prisoha [69]3 years ago

6 0

Answer:

The answer is 2.4%

Step-by-step explanation:

Citrus2011 [14]3 years ago

5 0

0.9%
round up to 1.0%

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A killer whale weighs 4.6 tons. Convert the weight to pounds.

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Answer:

9200

Step-by-step explanation:

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3 years ago

The city of Atlanta increased their sales tax from 7.5% t 8%. How much more tax would you pay on a $10 purchase?

butalik [34]

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Write answer as an inequality solved for c

g100num [7]

He will spend at least $27. He has already spent $16

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3 years ago

A grocer sells 30 loaves of bread a day. The cost is $2.50 per loaf. The grocer estimates that for each $0.50 increase in cost,

Viktor [21]

Answer:

none of the above

Step-by-step explanation:

The grocer's revenue will be the product of the number of loaves sold (30-2x) and their price (2.50+0.50x).

Revenue will be positive for values of x between those that make these factors be zero. The number of loaves sold will be zero when ...

... 30 -2x = 0

... 15 -x = 0 . . . . . divide by 2

... x = 15 . . . . . . . add x

The price of each loaf will be zero when ...

... 2.50 +0.50x = 0

... 5 + x = 0 . . . . . . . multiply by 2

... x = -5 . . . . . . . . . . subtract 5

Revenue will be positive for any number of increases greater than -5 and less than 15.

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D is the best of the offered choices, but it is incorrect in detail. -5 is a number less than 15, but will give zero revenue.

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3 years ago

In a circle, area and circumference can be found using the formulas A=(pi)r^2 and C=2(pi)r, respectively, Write a formula for A

AURORKA [14]

Answer:

$A = \dfrac{C^2}{4\pi}$

Step-by-step explanation:

Given that

Area of a circle $A=\pi r^2$

Circumference of the circle $C = 2 \pi r$

Let us re-write the equation of area of circle:

$A=\pi r^2$

$A = \pi \times r \times r$

Multiplying and dividing with 2:

$A = \dfrac{2\pi r}{2} \times r\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C}{2} \times r\\\text{Multiplying and dividing by } 2\pi:\\\Rightarrow A = \dfrac{C}{2} \times \dfrac{2\pi r}{2\pi}\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C \times C}{4 \pi}\\\Rightarrow A = \dfrac{C^2}{4 \pi}$

Hence, <em>A</em> in terms of <em>C</em> can be represented as:

$A = \dfrac{C^2}{4\pi}$

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3 years ago