The area of the kite is the amount of space it occupies
The area of the assumed kite is 25 square units
<h3>How to determine the area of the kite?</h3>
The question is incomplete, as the dimensions of the kites are not given.
So, I will provide a general explanation
The area of a kite is:
Area = 0.5pq
Where p and q are the lengths of the diagonals of the kite.
Assume that p = 5 and q = 10, for a kite.
The equation becomes
Area = 0.5 * 5 * 10
Evaluate
Area = 25
Hence, the area of the assumed kite is 25 square units
Read more about areas at:
brainly.com/question/24487155
Recall that
![(x+y)^2=x^2+2xy+y^2](https://tex.z-dn.net/?f=%28x%2By%29%5E2%3Dx%5E2%2B2xy%2By%5E2)
. So we can add twice the first equation to the second one to get
![x^2+y^2+2xy=10+2\cdot3\iff(x+y)^2=16\implies x+y=\pm4](https://tex.z-dn.net/?f=x%5E2%2By%5E2%2B2xy%3D10%2B2%5Ccdot3%5Ciff%28x%2By%29%5E2%3D16%5Cimplies%20x%2By%3D%5Cpm4)
Since
![xy=3](https://tex.z-dn.net/?f=xy%3D3)
, we have
![(x\neq0)](https://tex.z-dn.net/?f=%28x%5Cneq0%29)
so
![x+y=x+\dfrac3x=\pm4\implies x^2\mp4x+3=0](https://tex.z-dn.net/?f=x%2By%3Dx%2B%5Cdfrac3x%3D%5Cpm4%5Cimplies%20x%5E2%5Cmp4x%2B3%3D0)
If
![x+y=4](https://tex.z-dn.net/?f=x%2By%3D4)
, then
![x^2-4x+3=(x-3)(x-1)=0\implies x=3,x=1\implies y=1,y=3](https://tex.z-dn.net/?f=x%5E2-4x%2B3%3D%28x-3%29%28x-1%29%3D0%5Cimplies%20x%3D3%2Cx%3D1%5Cimplies%20y%3D1%2Cy%3D3)
If
![x+y=-4](https://tex.z-dn.net/?f=x%2By%3D-4)
, then
![x^2+4x+3=(x+1)(x+3)=0\implies x=-1,x=-3\implies y=-3,y=-1](https://tex.z-dn.net/?f=x%5E2%2B4x%2B3%3D%28x%2B1%29%28x%2B3%29%3D0%5Cimplies%20x%3D-1%2Cx%3D-3%5Cimplies%20y%3D-3%2Cy%3D-1)
So the solution set is
<h3>
Answer: 11/20</h3>
=====================================================
Work Shown:
x = unknown horizontal length
1/5 = 0.2
Perimeter = 2*(width + length)
P = 2*(0.2 + x)
P = 0.4 + 2x
Set this equal to the given perimeter of 1 & 1/2 = 1.5 and solve for x
0.4 + 2x = 1.5
2x = 1.5-0.4
2x = 1.1
x = (1.1)/2
x = 0.55
x = 55/100
x = (5*11)/(5*20)
x = 11/20
Answer:
288 × 60=17280 feet
Step-by-step explanation: