Question

A laboratory requires 2.0 L of a 1.5 M solution of hydrochloric acid (HCl), but the only available HCl is a 12.0 M stock solution. How could you prepare the solution needed for the lab experiment? show all work to find your answer

Answer 1

The amount of the solute is constant during dilution. So the mole number of HCl is 2*1.5=3 mole. The volume of HCl stock is 3/12=0.25 L. So using 0.25 L stock solution and dilute to 2.0 L.

Answer 2

Answer: The volume of stock HCl solution required to make laboratory solution will be 0.25L

Explanation:

To calculate the volume of stock solution required to make the laboratory solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of stock solution.

$M_2\text{ and }V_2$ are the molarity and volume of laboratory solution.

We are given:

$M_1=12M\\V_1=?L\\M_2=1.5M\\V_2=2L$

Putting values in above equation, we get:

$12\times V_1=1.5\times 2\\\\V_1=0.25L$

Hence, the volume of stock HCl solution required to make laboratory solution will be 0.25L