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2 years ago

Explain with the help of examples difference between elements and compounds

Chemistry

1 answer:

djyliett [7]2 years ago

5 0

Answer:

Elements are pure substances which are composed of only one type of atom. Compound are substances which are formed by two or more different types of elements that are united chemically in fixed proportions. ... Some of the examples of elements are Iron, Copper, Gold, etc. A few examples of compounds are NaOH, NaCl, etc.

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1- the Nalt and Gil- Cu2+ ad out- what are the spectator ions in this reaction

Mrac [35]

Answer:

cu2 is 5he correct answer

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1 year ago

I need some help please

Norma-Jean [14]

Answer:

the first one to the third box

the second one to the fourth box

the third one to second box

and the fourth one to the first box

Explanation:

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2 years ago

A physical change _____ change the composition or identity of the substance. will will not 2. An example of a physical change is

Sav [38]

Answer:

not sure

Explanation:

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3 years ago

Jason ran 5/7 of the distance around the school track sara ran 4/5 of Jason distance what fraction of the total distance around

FrozenT [24]

Let x represent the total distance around the track
Jason's distance: (5/7)x
Sara ran (4/5) of Jason's distance,
so she ran (4/5)*(5/7)x = (4/7)x
Sara ran 4/7 of the total distance

7 0

3 years ago

I need part 1 and 2 please , just separate answers

Vladimir79 [104]

First, we have to remember the molarity formula:

$M=\text{ }\frac{moles\text{ of solute}}{L\text{ solution}}$

Part 1:

In this case, our solute is sodium nitrate (NaNO3), and we have the mass dissolved in water, then we have to convert grams to moles. For that, we need the molecular weight:

$M.W_{NaNO_3}=\text{ 23+14+16*3= 85 g/mol}$

Then, we calculate the moles present in the solution:

$3.976\text{ g NaNO}_3\text{ * }\frac{1\text{ mol}}{85\text{ g}}=\text{ 0.04678 mol NaNO}_3$

Now, we have the necessary data to calculate the molarity (with the solution volume of 200 mL):

$M=\frac{0.04678\text{ mol}}{200\text{ mL*}\frac{1\text{ L}}{1000\text{ mL}}}=\text{ 0.2339 M}$

The molarity of this solution equals 0.2339 M.

Part 2:

In this case, we have the same amount (in moles and mass) of sodium nitrate, but a different volume of solution, then we only have to change it:

$M=\text{ }\frac{0.04678\text{ mol}}{275\text{ mL *}\frac{1\text{ L}}{1000\text{ mL}}}=\text{ 0.1701 M}$

So, the molarity of this solution is 0.1701 M.

5 0

9 months ago

Explain with the help of examples difference between elements and compounds​

Explain with the help of examples difference between elements and compounds