Answer:
a. True
Explanation:
The data curve for OCI-/H3O appears to be similar to C2H3O2-/H3O because protons have not dissociated with conjugate base. This conjugate base is strong and hold proton in solution while acids try to dissociate it.
A. Chloroplasts
B. The cell wall and the vacuole
C. Vacuoles
D. The mitochondrion
The energy of 393 kJ is released as heat. Then, the container will experience an increase of temperature and, given that it is sealed, also an increase of pressure.
The increase of temperature results from the heat developed during the reaction.
The increase of pressure results from the fact that that the solid carbon will become gaseuos carbon dioxide. This gas will occupy a larger volume than the solid carbon and also this elevation of the temperature will make the pressure of the gas inside the container increase.
Answer: 2elements sulfur and oxygen
Answer:
<em><u>PLZ</u></em><em><u> </u></em><em><u>MARK</u></em><em><u> </u></em><em><u>ME</u></em><em><u> </u></em><em><u>BRIANLIEST</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>REALLY</u></em><em><u> </u></em><em><u>WANT</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>PLZZZZZZ</u></em><em><u> </u></em><em><u>ISS</u></em><em><u> </u></em><em><u>GARIB</u></em><em><u> </u></em><em><u>KI</u></em><em><u> </u></em><em><u>DUA</u></em><em><u> </u></em><em><u>LAGEGI</u></em><em><u> </u></em><em><u>YARR</u></em><em><u> </u></em><em><u>PLZ</u></em>
Explanation:
<em>Glucose and galactose are monosaccharides that differ from one another only at position C-4. Thus, they are epimers that have an identical configuration in all the positions except in position C-4. ... Glucose and galactose are epimers that do not differ in position C-5 but differ in position C-4.</em>