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Aleks04 [339]
3 years ago
13

What are the vertical angles

Mathematics
2 answers:
wariber [46]3 years ago
8 0
It’s the bottom left answer because the angles are opposite of each other. They are also congruent. I hope this helps!
quester [9]3 years ago
7 0

Answer:

LMJ & MON

Step-by-step explanation:

vertical-

1)across from each other

2)congruent

3)must be formed from straight lines

4) made by intercepting line

ok so with that in mind LMJ & MON is the right answer.

LMJ & KJH  are not congruent nor are across from each other

LMJ & IJM are not congruent nor are across from each other

LMJ & NMJ are not congruent nor are across from each other

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2. Tristan wants to go bowling. He wants to spend no more than $25. It costs $3.00 to rent shoes and $4.50 for each game. What i
liubo4ka [24]

Answer:

3 + 4.50g \leq 25

g\leq 4

Step-by-step explanation:

25 - 3 is 22. 22 divided by 4.50 is a decimal. But it rounds down to 4. So the most amount of games Tristan can play is 4.

Hope it helps!

6 0
3 years ago
A large cube has 5 layers, each with 5 rows of 5 small cubes. How many small cubes will the larger cube contain? Explain Please
Flura [38]
125 because 5 times 5 times 5 equals 125
5 0
3 years ago
Read 2 more answers
Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,
vladimir1956 [14]

Answer:

(a) C(6,0) = 1, C(6,1) = 6, C(6,2) = 15, C(6,3) = 20, C(6,4) = 15, C(6,5) = 6, C(6,6) = 1.

(b) C(7,0) = 1, C(7,1) = 7, C(7,2) = 21, C(7,3) = 35, C(7,4) = 35, C(7,5) = 21, C(7,6) = 7, C(7,7)=1.

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

C(n,k) = \frac{n!}{k!(n-k)!}

where the symbol n! is the factorial and means

n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n.

By convention 0!=1. The most important property of the factorial is n!=(n-1)!\cdot n, for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

  • C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1
  • C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6
  • C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15
  • C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20
  • C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15
  • C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6
  • C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1.

(b) The explanations to the solutions is just the calculations.

  • C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1
  • C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7
  • C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21
  • C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35
  • C(7,4) = \frac{7!}{4!(7-4)!} = \frac{6!\cdot 7}{4!\cdot 3!} = frac{5!\cdot 6\cdot 7}{4!\cdot 6} = \frac{120\cdot 7}{24} = 35
  • C(7,5) = \frac{7!}{5!(7-2)!} = \frac{7!}{5!\cdot 2!} = 21
  • C(7,6) = \frac{7!}{6!(7-6)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7
  • C(7,7) = \frac{7!}{7!(7-7)!} = \frac{7!}{7!} = 1

For all the calculations just recall that 4! =24 and 5!=120.

6 0
3 years ago
W(n) = n + 3; Find the value of w(-5)<br> A) 2 <br> B) -2<br> C) 3<br> D) 1
Lina20 [59]

Answer:

-2

Step-by-step explanation:

-5 + 3 = -2

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

6 0
3 years ago
Which graph best represents the feasibility region for the system shown above? ( pics are in this)
zalisa [80]

Consider the system of inequalities

\left\{ \begin{array}{l}  y\ge 2 \\  x\le 6 \\  y\le 3x+2 \\  y\le -x+10. \end{array}\right.

1. Plot all lines that are determined by equalities (see attached diagram)

\left\{ \begin{array}{l}  y=2 \text{ (red line)} \\  x= 6  \text{ (blue line)}\\  y=3x+2 \text{ (green line)} \\  y= -x+10  \text{ (orange line)}. \end{array}\right.

2. Determine which bounded part of the plane you should select:

  1. y\ge 2 means that you should take points with y-coordinates greater than or equal to 2 (top part of the coordinate plane that was formed by the red line);
  2. x\le 6 means that you should take points with x-coordinates less than or equal to 6 (left part of the coordinate plane that was formed by the blue line);
  3. for y\le 3x+2 you can check where the origin is placed. Since 0\le 3\cdot 0+2, the origin belongs to the needed part and you have to take the right part of the coordinate plane that was formed by green line.
  4. for y\le -x+10 you can check where the origin is placed. Since 0\le -1\cdot 0+10, the origin belongs to the needed part and you have to take the bottom part of the coordinate plane that was formed by orange line.

3. According to the previous explanations, the shaded region is as in A diagram.

Answer: correct choice is A.


5 0
3 years ago
Read 2 more answers
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