Area of trapezium
= ½(a + b)h
= ½(15 + 10)(12)
= 150 feet²
Y=4x+12
y=-2(x+2)2+2=>y=-4x-4+2=-4x-2=>
y=-4x+2
Use the elimination property:
2y=14
y=7
Put y value back to the first equation: 7=4x+12, solve for x and -5=4xso x=-5/4
(-5/4,7)
Angle 1 and 3 are equals and 2 and 4 are the same
The area of the shaded part is: 42.14 ft² .
<h3>Area of Square</h3>
Area = s²
<h3>Area of Quarter Circle </h3>
Area = 1/4πr²
Thus:
Area of the shaded part of the figure = area of square - area of quarter circle
Area of shaded part = s² - 1/4πr²
s = 14 ft
r = 14 ft
Substitute
Area of shaded part = 14² - 1/4(3.14)(14²)
= 42.14 ft²
Therefore, the area of the shaded part is: 42.14 ft² .
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