Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: 
Where
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:

Substitute the respective values in the above formula.



Hence, the required probability is 0.55404.
Answer:
You say that everytime boy
Step-by-step explanation:
Answer:
0.118 is the probability someone will spend no more than 30 minutes reading online national news reports.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 49 minutes
Standard Deviation, σ = 16 minutes
We are given that the distribution of time an individual reads is a bell shaped distribution that is a normal distribution.
Formula:

P(no more than 30 minutes)

Calculation the value from standard normal z table, we have,

0.118 is the probability someone will spend no more than 30 minutes reading online national news reports.
2x-y=7
y=2x+3
Substitute (2x+3) in for y in the first equation
2x-(2x+3)=7
2x-2x-3=7
-3=7
Becuase -3 does not equal 7 the answer is no solution