Answer:
The answer is D or Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle T"U"V" . I just took the test and I hope I helped : )
Step-by-step explanation:
Answer:
32,768.
Step-by-step explanation:
There are 12 lots of 5 minutes in 1 hour.
The equation is 8*(2^12)
= 8 * 4096
= 32,768.
Point P is certainly the outlier because the other points are all consistent with the string of data while Point P is alone with no other data around it.
The Big O notation of the composite function 5N^3 O(N^2) is c. O(N^3).
A composite function of two capabilities combines the given two functions inside the given order. i.e., for any given functions f(x) and g(x), there may be four composite functions: f(g(x)) that is substituting g(x) into f(x) g(f(x)) that's substituting f(x) into g(x).
A composite characteristic is a function that relies upon any other feature. A composite characteristic is created while one characteristic is substituted for another feature. For instance, f(g(x)) is the composite function that is fashioned whilst g(x) is substituted for x in f(x). f(g(x)) is studied as “f of g of x”.
In Maths, the composition of a character is an operation wherein two capabilities say f and g generate a brand new feature say h in one of these manners that h(x) = g(f(x)). It method right here feature g is implemented to the function of x. So, basically, a feature is carried out to the result of every other feature.
Learn more about composite functions here brainly.com/question/10687170
#SPJ4
<h3>
Answer:</h3>
- Find the composite of the functions
- x/3
- All the answers are correct
- f(x) = 2+∛(x/3)
- f(x) = (x+3)/2
<h3>
Step-by-step explanation:</h3>
1. If f(x) and g(x) are inverse functions, then f(g(x)) = g(f(x)) = x. Finding the composite of the two functions will tell you if they are inverses.
2. To find the inverse of a function, swap x and y, then solve for y.
... x = 3y
... x/3 = y . . . . . matches f(x) = x/3
3. A function will pass the vertical line test. If its inverse is also a function, that, too, will pass the vertical line test. Since the inverse of a function is that function reflected across y=x, any inverse function that passes the vertical line test corresponds to an original function that passes the horizontal line test. (A vertical line reflected across y=x is a horizontal line.)
4. See 2.
... x = 3(y -2)³
... (x/3) = (y -2)³ . . . . divide by 3
... ∛(x/3) = y -2 . . . . .take the cube root
... 2+∛(x/3) = y . . . . .add 2
... f(x) = 2+∛(x/3) . . . . is the inverse
5. See 2.
... x = 2y -3
... x+3 = 2y . . . . . add 3
... (x+3)/2 = y . . . .divide by 2
... f(x) = (x+3)/2 . . . . is the inverse
