The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Given that,
- The ground temperature at the airport is 10 °C.
- The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.
Based on the above information, the temperature outside should be
The decrease in the temperature should be
= 5.4×5
= 27°C
Now the final temperature is
= 10 - 27
= -17°C
Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Learn more: brainly.com/question/20459283
Since it is an isosceles trapezoid;
AB=CD which means;
5y-3=6y-17
get the variables to one side and you get:
-3=y-17
Then add 17 to both sides and
14=y
Therefore y=14 is your answer
Answer:

Step-by-step explanation:
<u><em>The correct question is</em></u>
1x10 to the fifth power over 4x10 to the negative fourth power given on scientific notation
we know that
To divide two numbers in scientific notation, divide their coefficients and subtract their exponents.
we have

The vector PQ is Q-P = (2, 1). The vector SR is R-S = (2, 2). One is not a multiple of the others, so the vectors are not parallel. In a parallelogram, these vectors would be identical. PQRS is
not a parallelogram.
Answer:
<h3> a₁ = -1</h3>
Step-by-step explanation:
