Answer:
Approximately nineteen percent of the service calls take more than 92.6 minutes.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Approximately nineteen percent of the service calls take more than how many minutes?
This is the value of X when Z has a pvalue of 1 - 0.19 = 0.81. So it is X when Z = 0.88.
Approximately nineteen percent of the service calls take more than 92.6 minutes.
Her account should have a total of $468.98 if she doesn't withdraw any money from her account
HIJ= 128 degrees
Explanation:
127x - 1 = 100 + 25x + 1
127x - 1 = 101 + 25x
-25x -25x
102x - 1 = 101
+1 +1
102x = 102
/102 /102
x = 1
y=3.009x-77.131 ~~ y=3.009(275)-77.113
y=3.009(275)-77.113 = y=827.475-77.113 = 750.362 ~~ 750
The answer is: A. $750
<em>Hoped this helped!</em>