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vlada-n [284]
3 years ago
5

What is the volume of this cube? Enter you answer as a decimal in the box.

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
5 0
Solution: V=a^3=3=0.5^3=0.125 
so your answer is 0.13, hope this helps!
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Please answer I will give BRAINLIEST if i can
N76 [4]

Answer:

Glass A holds the most, It holds more than glass B because of its cone shape.

Step-by-step explanation:

I hope I helped you, now have a good day and good luck!! ;)

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3 years ago
What is the equation in point slope form of the line that passes through the point (–1,–3) and has a slope of 4?
Law Incorporation [45]
M=4

(-1, -3)
x1, y1

just plug the rest in

4 0
3 years ago
Read 2 more answers
X=25.36+0.45(25.36)<br><br> LaTeX: x=
e-lub [12.9K]

Answer:

x=36.772  

Step-by-step explanation:

Given : Expression x=25.36+0.45(25.36)

To find : Solve the expression ?

Solution :

Step 1 - Write the expression,

x=1(25.36)+0.45(25.36)

Step 2 - Apply distributive, ab+ac=a(b+c)

Here, a=25.36, b=1, c=0.45

x=25.36(1+0.45)

Step 3 - Solve the expression,

x=25.36\times 1.45

x=36.772

Therefore, x=36.772

7 0
3 years ago
There is an equal number of men, women and children at a party. How many persons could be at the party?
astra-53 [7]

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3, 6, 9, 12, and so on, basically any number that can be divided by 3

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2 years ago
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Kitty [74]

Answer:   (-2, 5) and (2, -3)

<u>Step-by-step explanation:</u>

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

        y - intercept = (0, 1)            2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\

         vertex = (1, -4)                2nd point (y-intercept) = (0, -3)


<em>see attached</em> - the graphs intersect at two points:  (-2, 5) and (2, -3)


8 0
3 years ago
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