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lesantik [10]
3 years ago
14

Find the product -a^4(7a^5- 5a+ 5)

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0
-a^4(7a^5- 5a+ 5) = - 7a^{9} +5 a^{5} -5 a^{4}
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The Bayside Bugle charges by the word to run automotive ads. The newspaper
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Answer:

$20.45

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Since the Bayside Bugle charges $18 for the first 20 words and there is more than 20 words in the ad you take 27-20 and you get 7 additional words.

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Since we have 7 additional words we multiply that by 0.35 cents and you get $2.45.

Next we add up our two numbers (2.45+18) we get the total of $20.45 fro a 27-word ad.

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Find the value of 5x - 2y+ 3z when x = 7 , y = 11 and z = -1
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7 0
2 years ago
Factor 26r3s + 52r5 – 39r2s4.
algol [13]

Answer:

13r²(2rs + 4r³ - 3s⁴)

Step-by-step explanation:

In equation 26r³s + 52r⁵ - 39r²s⁴;

The GCF of 26, 52, and 39 = 13

The GCF of r³, r⁵ and r² = r²

The GCF of s, (no "s"), and s⁴ = no "s" (Since one of the number doesn't have "s")

Now we can factor out 13r² from all three expressions;

26r³s + 52r⁵ - 39r²s⁴

=> <em>13r²(2rs) + 13r²(4r³) - 13r²(3s⁴)</em>

To factor it all together;

<u>13r²(2rs + 4r³ - 3s⁴)</u>

Hope this helps!

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2 years ago
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