Find the product -a^4(7a^5- 5a+ 5)

Mathematics

1 answer:

Nostrana [21]3 years ago

3 0

$-a^4(7a^5- 5a+ 5) = - 7a^{9} +5 a^{5} -5 a^{4}$

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Show that the two triangles given beside are similar and calculate the lengths of sides PQ and PR.

Rina8888 [55]

9514 1404 393

Answer:

ΔABC ~ ΔPQR
PQ = 8
PR = 14

Step-by-step explanation:

Angles A and P are marked congruent; angles B and Q are marked congruent, so the triangles are similar by the AA similarity postulate. The similarity statement can be written ...

ΔABC ~ ΔPQR by AA similarity

The ratio of sides of PQR to ABC is the ratio QR/BC = 12/6 = 2. That is, each side in the larger triangle is 2 times the length of the corresponding smaller side.

PQ = 2·AB = 2·4 = 8

PR = 2·AC = 2·7 = 14

The side lengths of interest are ...

PQ = 8, PR = 14

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Answer:

Step-by-step explanation:

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klasskru [66]

I believe the answer might be:
x = 28/19

Steps:
Expand
3(5 - x)/2 - 4(3 + 2x)/5

-3x + 15 - 8x + 12
------------ -----------
2 5

Find the LCD for the equation above:
(15-3x) * 5 - (12+8x) * 2
------------- --------------
10 10

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5(-3+15) - 2(8x+12)
--------------------------
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-----------
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3 years ago

I’m so bad at slope

Travka [436]

Answer:

So slope 1 would be positive

Slope 2 would be negative

Slope 3 would be zero

Step-by-step explanation:

If the slope is moving up from left to right, then it is positive

If the slope is moving down from left to right, then it is negative

If the slope is a vertical line and is not moving left/right, then it is undefined