Given:
Irregular Shape:
Semi-circle and rectangle:
Area of a rectangle = l * w
Area of a semi-circle = (π r²)/2
Area of rectangle = 8 cm * 5 cm = 40cm²
Area of a semi-circle = (3.14 (4²))/2 = (3.14*16)/2 = 50.24/2 = 25.12cm²
4² is taken from diameter of 8cm divided by 2 to get the radius.
Total area = 40 cm² + 25.12 cm² = 65.12 cm²
The answer is 28
work shown in picture below
Answer:324
Step-by-step explanation:
int i = 42.7; /* konwersja z double do int */
float f = i; /* konwersja z int do float */
double d = f; /* konwersja z float do double */
unsigned u = i; /* konwersja z int do unsigned int */
f = 4.2; /* konwersja z double do float */
i = d; /* konwersja z double do int */
char *str = "foo"; /* konwersja z const char* do char* [1] */
const char *cstr = str; /* konwersja z char* do const char* */
void *ptr = str; /* konwersja z char* do void* */
Podcza
-3^3=9
18-9+3•2
9+3•2
12•2
24
Answer:
x >= 20
Step-by-step explanation:
Solve for x:
Start to isolate x by subtracting the 6 from both sides.
Then multiply 10 from each side.
After that, you would get x >= 20
