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gogolik [260]
3 years ago
5

How many 1/4 teaspoon doeses are in 7/8

Mathematics
2 answers:
Elden [556K]3 years ago
8 0

There are 3 1/2 doses

sveticcg [70]3 years ago
3 0

namely, how many times does 1/4 go into 7/8?


\bf \cfrac{7}{8}\div \cfrac{1}{4}\implies \cfrac{7}{8}\cdot \cfrac{4}{1}\implies \cfrac{7}{1}\cdot \cfrac{4}{8}\implies \cfrac{7}{1}\cdot \cfrac{1}{2}\implies \cfrac{7}{2}\implies 3\frac{1}{2}

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One pound of grapes costs $1.55. Which equation correctly shows a pair of equivalent ratios that can be used to find the cost of
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Answer:

StartFraction 1.55 over 1 EndFraction = StartFraction x over 3.5 EndFraction

Step-by-step explanation:

\frac{1.55}{1}  =  \frac{x}{3.5}  \\  \\  \therefore \: x = 1.55 \times 3.5 \\  \\ \therefore \: x = \$ 5.425 \\  \\\therefore \: x\approx  \$5.43

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What is the length of side AD?. . . 6 cm. 8.5 cm. 10.4 cm. 12 cm
ludmilkaskok [199]
In triangle ABC, AC = 12/ (sin30) = 12 / (1/2) = 24
DC = 24-x
DB = DC tan 30 = (24-x)  tan30 <span>=(24−x)/</span><span>√3
</span>

In triangle ADB using Pythagorean Theorem<span><span>x2</span>+((24−x)/<span>√3</span><span>)2</span>=<span>12^2</span></span><span><span>x2</span>+(24−x<span>)^2</span>/3=<span>12^2</span></span><span>3<span>x2</span>+(24−x<span>)^2</span>=432</span><span>4<span>x2</span>−48x+576=432</span><span>4<span>x2</span>−48x+144=0</span><span><span><span>x2</span>−12x+36=0
x1 = x2 =6

AD = AC - DC = 24- (24-x) = 6</span></span>
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Find the first three terms of the sequence below n² – n + 4
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Answer:

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Step-by-step explanation:

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The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

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