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2 years ago

7

Mrs. Winter's students reported the amount of time they spent reading last night. The line plot shows the fraction of an hour ea

ch student spent reading. How much total time did Mrs. Winter's students spend reading last night?

1 answer:

ad-work [718]2 years ago

5 0

Answer:

A. 10:45 HOURS

Step-by-step explanation:

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Ms. Wiltz has a $20 gift certificate to her local bakery. If she buys a loaf of banana nut bread for $8.30 and uses the rest of

sladkih [1.3K]

Answer:

20-8.30=11.70

11.70 she is able to buy 11 brownies

Step-by-step explanation:

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3 years ago

Which of the following numbers is the greatest?<br><br>2.5<br>-2.5<br>0<br>-7

vodka [1.7K]

Answer:

2.5

Step-by-step explanation:

2.5 is the only positive number amongst the options, so it must be the greatest.

4 0

1 year ago

Read 2 more answers

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago

Paula is training take part in a fun run fir charity. Paula weighed 65.5 kilogram before she started her training. She has list

lesantik [10]

We can convert grams to kilograms by dividing by 1000.
3500÷1000=3.5kg

Now we subtract this from her original weight
65.5-3.5= 62kg

8 0

2 years ago

What is the slope of a line perpendicular to the line whose equation is

GenaCL600 [577]

Answer:

The slope or incline is -5

Step-by-step explanation:

rewrite to get the form

y = ...

x - 5y = -10

- 5y = -10 -x

divide left and right if the = sign by -5 gives:

(-5/-5)y = (-1/-5)x + (-10/-5)

y = 1/5x +2

So the incline is 1/5

a perpendicular line has an incline of -1 *5/1 = -5

The slope or incline is -5

4 0

3 years ago