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Svetach [21]
4 years ago
14

7. Given x = -x^2-3x+10

Mathematics
1 answer:
beks73 [17]4 years ago
6 0

Step-by-step explanation:

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Alice, Ben, and Calvin are waiting at a taxi stand, since taxis are the only ride service in this town. Although they haven’t me
mr_godi [17]

Answer: $17.78; 26.67; 35.56

Step-by-step explanation:

Given the following information.:

Price of cab = $2 per mile , irrespective of the number of passengers.

Alice's destination = 20 miles

Ben's destination = 30 miles

Calvin's destination = 40 miles

If the three share a cab, the cab fee will be (cost per mile * number of miles of the farthest destination).

($2 * 40) = $80

Let price = a, for 20 miles

Ben's mile = 30 miles = 1.5 times Alice's miles, then Ben's pay = (1.5a)

Calvin's mile = 40 miles = 2 times Alice's miles, then Calvin's pay = (2a)

Thus,

a + 1.5a + 2a = $80

4.5a = $80

a = $80 / 4. 5

a = $17.78

Ben's pay = 1.5a = $26.67

Calvin's pay = 2a = $35.56

8 0
3 years ago
Tens and ones combinations. 30 + ? + ? + ? / ? + ? = 92
BlackZzzverrR [31]

i know the answer its 90

3 0
3 years ago
Read 2 more answers
Bananas are curved because they grow towards the sun ☀️
Advocard [28]
It would be

14,494.2 - 282.6 = 14211.6
6 0
3 years ago
Read 2 more answers
Calculus Help Show that one function is not an antiderivative of another
liraira [26]

Just differentiate <em>G</em> and <em>H</em> :

• d<em>G</em>/d<em>x</em> = d(<em>x</em> ² <em>eˣ </em>)/d<em>x</em> = 2<em>x</em> <em>eˣ</em> + <em>x</em> ² <em>eˣ</em>

so <em>G</em> is not an antiderivative of <em>f</em>.

• d<em>H</em>/d<em>x</em> = d(2<em>x</em> <em>eˣ</em> - 2<em>eˣ</em> ) = (2<em>eˣ</em> + 2<em>x</em> <em>eˣ</em> ) - 2<em>eˣ</em> = 2<em>x</em> <em>eˣ</em> = <em>f(x)</em>

so <em>H</em> is indeed an antiderivative of <em>f</em>.

6 0
3 years ago
Please solve with explanation
photoshop1234 [79]

Answer:

Below in bold.

Step-by-step explanation:

If the 3 points are on the circle with the given center then the distance from each point to the center will all be equal. This distance will be the radius of the circle.

Distance  of P (2, 5) from the center (4, 2)

= √( (5-2)^2 + (2-4)^2)

= √(9 + 4)

= √13.

For Q (6, -1)this distance is:

= √(6-4)^2 + (-1-2)^2)

= √13.

For R (7, 4) his distance is:

= √(7-4)^2 + (4-2)^2)

= √13

These distances are the same so the points P, Q and R lie on the circle.

The midpoint of PQ

= (2+6)/2 , (5 - 1)/2

= (4, 2).

Which is the center so this verifies the second part.

6 0
2 years ago
Read 2 more answers
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