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Gelneren [198K]
3 years ago
15

la potencia que necesita una grúa que realiza un trabajo de 1800J para elevar un coche en 100 segundos.

Physics
1 answer:
butalik [34]3 years ago
8 0

Answer:

P = 18 Watts

Explanation:

La formula es la siguiente:

P = W/t donde P es la potencia, W el trabajo realizado y t el tiempo transcurrido. Por lo tanto, reemplazando los valores dados en el problema obtenemos:

P = 1800 J / 100 seg

P = 18 Watts

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AlexFokin [52]

Yes, but it's a null vector .So,no vector can have a component at right angle to itself unless it is a zero vector.

5 0
4 years ago
A mass m = 4.6 kg hangs on the end of a massless rope L = 2.16 m long. The pendulum is held horizontal and released from rest.
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ind the velocity my using the conservation of energy mgh=1/2mv^2. At the bottom, the mass is turning in a circle with tension pointing up towards the center of the circle and weight pointing down. Use the centripetal force requirement mv^2/r=T-W and solve for T. Hope this helps.

4 0
3 years ago
A 2-kW electric heater takes 15 min to boil a quantity of water. If this is done once a day and power costs 10 cents per kWh, wh
frozen [14]

Answer:

<h2> $1.50</h2>

Explanation:

Given data

power P= 2 kW

time t= 15 min to hours = 15/60= 1/4 h

cost of power consumption per kWh= 10 cent = $0.1

We are expected to compute the cost of operating the heater for 30 days

but let us computer the energy consumption for one day

Energy of heater  for one day= 2* 1/4 = 0.5 kWh

the cost of operating the heater for 30 days= 0.5*0.1*30= $1.50

<u><em>Hence it will cost  $1.50 for 30 days operation</em></u>

4 0
3 years ago
A billiard ball is moving in the x-direction at 30.0 cm/s and strikes another billiard ball moving in the y-direction at 40.0 cm
PSYCHO15rus [73]

Explanation:

Given that,

Initial speed of the billiard ball 1, u = 30i cm/s

Initial speed of another billiard ball 2, u' = 40j cm/s

After the collision,

Final speed of first ball, v = 50 cm/s

Final speed of second ball, v' = 0 (as it stops)

Let us consider that both balls have same mass i.e. m

Initial kinetic energy of the system is :

K_i=\dfrac{1}{2}mu^2+\dfrac{1}{2}mu'^2\\\\K_i=\dfrac{1}{2}m(u^2+u'^2)\\\\K_i=\dfrac{1}{2}m((30)^2+(40)^2)\\\\K_i=1250m\ J

Final kinetic energy of the system is :

K_f=\dfrac{1}{2}mv^2+\dfrac{1}{2}mv'^2\\\\K_f=\dfrac{1}{2}m(v^2+v'^2)\\\\K_f=\dfrac{1}{2}m((50)^2+(0)^2)\\\\K_f=1250m\ J

The change in kinetic energy of the system is equal to the difference of final and initial kinetic energy as :

\Delta K=K_f-K_i\\\\\Delta K=1250m-1250m\\\\\Delta K=0

So, the change in kinetic energy of the system as a result of the collision is equal to 0.    

7 0
4 years ago
Which of the following is a scientific law?
Varvara68 [4.7K]

Answer:

B. For a gas in a closed container at a constant temperature, the product of the pressure and the volume remains constant.

Explanation:

The rest are societal laws, as they are telling you something you should avoid or follow.

Hope this helps :)

7 0
3 years ago
Read 2 more answers
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