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soldier1979 [14.2K]
3 years ago
9

A ball of radius r rolls on the inside of a track of radius R. If the ball starts from rest at the vertical edge of the track, w

hat will be its speed when it reaches the lowest point of the track, rolling without slipping? Express your answer in terms of the variables R, r, and the constant g.

Physics
1 answer:
natka813 [3]3 years ago
5 0

Answer:

Detailed solution is given

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A 3.0-kg block starts at rest at the top of a 37° incline, which is 5.0 m long. Its speed when it reaches the bottom is 2.0 m/s.
Mama L [17]

Answer: f_{r} = 16.49N

Explanation: The object is placed on an inclined plane at an angle of 37° thus making it weight have two component,

W_{x} = horizontal component of the weight = mgsinФ

W_{y} = vertical component of weight = mgcosФ

Due to the way the object is positioned, the horizontal component of force will accelerate the object thus acting as an applied force.

by using newton's law of motion, we have that

mgsinФ - f_{r} = ma

where m = mass of object=5kg

a = acceleration= unknown

Ф = angle of inclination = 37°

g = acceleration due to gravity = 9.8m/s^{2}

f_{r} = frictional force = unknown

we need to first get the acceleration before the frictional force which is gotten by using the equation below

v^{2} = u^{2} + 2aS

where v = final velocity = 2m/s

u = initial velocity = 0m/s (because the object started from rest)

a= unknown

S= distance covered = length of plane = 5m

2^{2} = 0^{2} + 2*a*5\\\\4= 10 *a\\\\a = \frac{4}{10} \\a = 0.4m/s^{2}

we slot in a into the equation below to get frictional force

mgsinФ - f_{r} = ma

3 * 9.8 * sin 37 - f_{r} = 3* 0.4

17.9633 - f_{r} =  1.2

f_{r} = 17.9633 - 1.2

f_{r} = 16.49N

4 0
4 years ago
What is a prediction
faust18 [17]
An educated guess about something. (What might happen in the future)
7 0
3 years ago
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Which of these BEST describes the concept of the rock cycle?
choli [55]
D  rocks are continually changing and type of rock mat be transformed into another type of appropriate process.

8 0
3 years ago
A 6 cm object is 15 cm from a convex lens that has a focal length of 5 cm. What is the distance of the image from the lens, to t
sweet [91]
So we want to know what is the distance d of the object from the lens if the height of the object is h=6 cm, focal length of the lens is f=5 cm and the distance d=15 cm is the distance of the object from the lens. From the formula for the convex lens 1/f=(1/D + 1/d) where D is the distance of the image from the lens we can get D after solving for D: 1/D=(1/f) - (1/d),
1/D=(1/5)-(1/15)=0.2-0,06667=0.13333 so f=1/0.13333=7.500187 cm. Rounded to the nearest hundredth D=7.50 cm.  That is very close to 7.69 cm so the correct answer is the third one. 
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3 years ago
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3. A drill spins with a frequency of 1200 RPM (revolutions per minute). What is its
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Your answer is 20
just take 1,200 divided by 60 [second] :)
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