When the object is at the focal point the angular magnification is 2.94.
Angular magnification:
The ratio of the angle subtended at the eye by the image formed by an optical instrument to that subtended at the eye by the object when not viewed through the instrument.
Here we have to find the angular magnification when the object is at the focal point.
Focal length = 6.00 cm
Formula to calculate angular magnification:
Angular magnification = 25/f
= 25/ 8.5
= 2.94
Therefore the angular magnification of this thin lens is 2.94
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Explanation:
the pressure is given by P=hpg
where h is height,p is density, g is 10m/s²
thus P= 0.05m•13.6x10³•10
P=6.8x10³ Hgmm
Answer:
I think its 9.0397 Ohms
Explanation:
take the reciprocal of all the resistances: 1/15, 1/65, 1/35
then add them: = 151/1365
then reciprocal the answer: =1365/151
And chuck it on a calculator: =9.04 Ohms
I think this is right but I'm not entirely sure. Tell me if I'm right by the way!
<span>As the marble leaves the table at two different speeds, its
horizontal velocity changes, but its vertical velocity does not.</span>
The value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g
<h3>
What is Mass and Weight ?</h3>
Mass is the quantity of matter. While weight is a gravitational pull on an object. Mass is measured in Kg while weight is measured in Newton.
What value should be reported for the total mass of three samples of iron weighing 117.0 g, 19.43 g, and 6.1043 g?
The total mass will be the sum of the three masses.
The total mass = 117 + 19.43 + 6.1043
The total mass = 142.5343 g
Convert gram to kilogram by dividing the answer by 1000
The total mass = 142.5343/1000
The total mass = 0.1425343 Kg
Therefore, the value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g approximately
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