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Irina18 [472]
3 years ago
10

two trucks leave at different times (from the same place) headed for the same city. Both trucks arrive at the same time. Based o

n the this information, which of the following statements is true? A. The trucks traveled the same distance in the same amount of time B. The trucks were traveling at the same average speed C. The trucks traveled different distances D. The truck that left later traveled faster
Physics
2 answers:
PIT_PIT [208]3 years ago
6 0
The answer is A because everything would have to be constant to arrive at the same place at the same time and A is the only option that is constant
Vedmedyk [2.9K]3 years ago
4 0

Answer:

A

Explanation:

If two trucks leave at different times from the same place, headed for the same city, then one thing out of the rest that is true is that the trucks traveled at the same distance in the same amount of time. Hope this helps!

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The sum of the two vectors in A, B, and C is equal to the sum of the two vectors above the line.  The sum of the two vectors in D isn't.

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3 years ago
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A cyclist makes the following trip along two vectors; he travels 9km to the north and then travels 6km to the east​
elena-14-01-66 [18.8K]

Answer:

Final distance from the origin: 10.82 km. the vector points as shown in the attached image.

Angle with respect to the east: 56.31^o

Explanation:

Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.

So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.

We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:

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Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.

Now, to find the value of the angle \theta, we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

tan(\theta)=\frac{opp}{adj} \\tan(\theta)=\frac{9}{6}\\tan(\theta)=\frac{3}{2}\\

Now we can find the value of the angle by using the arctan function:

tan(\theta)=\frac{3}{2} \\\theta=arctan(\frac{3}{2} )\\\theta= 56.31^o

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Answer:

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3 years ago
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