Answer:1) 100 gm mass should be placed at 95 cm mark.
2) Mass of 112.5 gm should be placed at 90 cm mark.
Explanation:
For equilibrium of the meter stick the sum of the moment's generated by the masses should be equal and opposite
Answer to part b)
Since a meter stick is 100 cm long and it is pivoted at it's center i.e at 50 cm
Thus
1) Moment generated by 100 gm mass about center =
Let a mass 'm' be placed at 90 cm mark thus moment it generates equals
Equating both the moments we get
Answer to part a)
Let the 100 grams weight be placed at a distance 'x' right of center
Moment generated by 100 grams weight equals
equating the moments of the forces we get
thus the mass of 100 gm should be placed at 95 cm mark in the scale.
Answer:
D. has no overall force acting on it.
Explanation:
Why?
Because in a straight line at the constant speed means the car moving in the same velocity, which is not acceleration neither deceleration, and it cannot be on a downhill slope. So the correct answer is
<h3>→ D. has no overall force acting on it.</h3>
Answer:
ΔS=2*m*Cp*ln((T1+T2)/(2*(T1*T2)^1/2))
Explanation:
The concepts and formulas that I will use to solve this exercise are the integration and the change in the entropy of the universe. To calculate the final temperature of the water the expression for the equilibrium temperature will be used. Similarly, to find the change in entropy from cold to hot water, the equation of the change of entropy will be used. In the attached image is detailed the step by step of the resolution.
Answer:
C
Explanation:
Force is a vector quantity. So, it has magnitude and direction which can also be describe as strength and direction
They use sound waves that bounce off walls, and other things back to them to feel where they are going.