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PIT_PIT [208]
3 years ago
5

During lightning strikes from a cloud to the ground, currents as high as 2.50×10^4 Amps can occur and last for about 40.0 micros

econds . How much charge is transferred from the cloud to the earth during such a strike?
Physics
1 answer:
dangina [55]3 years ago
6 0

Answer:

1 C

Explanation:

The intensity of electric current is defined as

I=\frac{q}{t}

where

I is the current

q is the amount of charge transferred

t is the time interval during which the charge is transferred

For the lightning in this problem, we have

I=2.50\cdot 10^4 A is the current

t=40.0 \mu s = 40.0\cdot 10^{-6} s is the time interval

Solving the formula for q, we find the amount of charge transferred:

q=I t = (2.50\cdot 10^4 A)(40.0\cdot 10^{-6}s)=1 C

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Answer:

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Explanation:

Given

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(h_1,P_1) = (0,101.325)

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Required

Determine the linear equation for P in terms of h

First, we calculate the slope/rate (m);

The following formula is used:

m = \frac{P_2 - P_1}{h_2 - h_1}

Substitute values for P's and h's

m = \frac{83.347 - 101.325}{1609.344- 0}

m = \frac{-17.978}{1609.344}

m = -\frac{17.978}{1609.344}

Multiply by 1000/1000

m = -\frac{17.978 * 1000}{1609.344*1000}

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The equation is then calculated using:

P - P_1 = m(h - h_1)

Substitute values for m, h1 and P1

P - P_1 = m(h - h_1)

P - 101.325 = -\frac{17978}{1609344}(h - 0)

P - 101.325 = -\frac{17978}{1609344}(h)

Make P the subject

P = -\frac{17978}{1609344}(h)+101.325

<em>The above is the required linear equation</em>

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