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3 years ago

9

Space shuttle Max is one of the extreme rides in enchanted kingdom. The first of its kind in the country, this roller coaster ri

de inverts its riders six times. If during one of its operations, a 53 kg boy experiences a net force of 1800N at the bottom of its rollercoaster loop, how fast would he be accelerating at this location?

1 answer:

Nastasia [14]3 years ago

4 0

Answer:

$Acceleration = 33.96ms^{-2}$ <em />

<em />

Step-by-step explanation:

Given

$Mass = 53kg$

$Force = 1800N$

Required

Determine the acceleration

The relationship between force, mass and acceleration is:

$Force = Mass * Acceleration$

Substitute values for Force and Mass

$1800 = 53 * Acceleration$

Solve for Acceleration

$Acceleration = 1800/53$

$Acceleration = 33.9622641509$

$Acceleration = 33.96ms^{-2}$ <em>---- Approximated</em>

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1 year ago

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3 years ago

Read 2 more answers

Zene deposited $50 in a savings account earning 5% interest, compounded annually. To thenearest cent, how much will he have in 3

JulsSmile [24]

Answer:

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we know that

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3 years ago

Find the value of questions

Zolol [24]

Answer:

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$\frac{3^9y}{2\times \:81}=\frac{243y}{2}$

Step-by-step explanation:

Given the expression

$\frac{3^9\times \:y}{2\times 81}$

solving the expression

$\frac{3^9\times \:y}{2\times 81}=\frac{3^9y}{162}$

$=\frac{3^9y}{3^4\times \:2}$ ∵ $162=3^4\times \:2$

$=\frac{3^5y}{2}$ ∵ $\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

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Therefore, the simplified expression is:

$\frac{3^9y}{2\times \:81}=\frac{243y}{2}$

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2 years ago