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ss7ja [257]
4 years ago
7

A-29 B-81 C-87 D-93 Please someone help I don’t get this

Mathematics
1 answer:
seropon [69]4 years ago
4 0

Answer:

B-29...b-29...b-29...B-29... B-29

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A Sum of $14 is made of 92 coins consisting of dimes and quarters. How Many are there of each kind of coin
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So first I would say, what if all of them were dimes, how far away would it be from $14?

So 92 coins * 10 cents = $9.20

So it's 4.80 dollars away from 14 dollars.

So if we were to switch one to a quarter, it would increase by 0.15 cents.

So we want to see how many increases we need to reach 4.80 dollars more.

4.80/0.15 = 32

So there are 32 quarters and 60 dimes.
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You have 10 fewer quarters than dimes and 5 fewer nickels than quarters. the total value of the coins is $4.75. Set up a system
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The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st
Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

v=\frac{d}{t}.

Applying this to our problem we have that

v=\frac{200m}{6.509s}= 30.726m/s.

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that v=\frac{d}{t}. This formula implies that

  1. t=\frac{d}{v}.

First, observer that 19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s.

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.

Then, applying 1) we have that

t=\frac{200m}{36.003m/s}=5.5549s.

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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